{
 "cells": [
  {
   "cell_type": "markdown",
   "id": "0",
   "metadata": {
    "slideshow": {
     "slide_type": "slide"
    }
   },
   "source": [
    "# Use FLAML to Tune Large Language Models\n",
    "\n",
    "`flaml.autogen` offers a cost-effective hyperparameter optimization technique [EcoOptiGen](https://arxiv.org/abs/2303.04673) for tuning Large Language Models. The research study finds that tuning hyperparameters can significantly improve the utility of LLMs.\n",
    "\n",
    "In this notebook, we tune OpenAI ChatGPT models for math problem solving. We use [the MATH benchmark](https://crfm.stanford.edu/helm/latest/?group=math_chain_of_thought) for measuring mathematical problem solving on competition math problems with chain-of-thoughts style reasoning.\n",
    "\n",
    "\n",
    "## Requirements\n",
    "\n",
    "FLAML requires `Python>=3.8`. To run this notebook example, please install the following packages:"
   ]
  },
  {
   "cell_type": "code",
   "execution_count": null,
   "id": "1",
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     "text": [
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      "Requirement already satisfied: pytz>=2020.1 in /home/trusted-service-user/cluster-env/trident_env/lib/python3.11/site-packages (from pandas->datasets==2.14.6) (2024.1)\n",
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      "Requirement already satisfied: six>=1.5 in /home/trusted-service-user/cluster-env/trident_env/lib/python3.11/site-packages (from python-dateutil>=2.8.2->pandas->datasets==2.14.6) (1.16.0)\n",
      "\n",
      "\u001b[1m[\u001b[0m\u001b[34;49mnotice\u001b[0m\u001b[1;39;49m]\u001b[0m\u001b[39;49m A new release of pip is available: \u001b[0m\u001b[31;49m23.3.1\u001b[0m\u001b[39;49m -> \u001b[0m\u001b[32;49m24.2\u001b[0m\n",
      "\u001b[1m[\u001b[0m\u001b[34;49mnotice\u001b[0m\u001b[1;39;49m]\u001b[0m\u001b[39;49m To update, run: \u001b[0m\u001b[32;49mpython -m pip install --upgrade pip\u001b[0m\n",
      "Note: you may need to restart the kernel to use updated packages.\n",
      "Warning: PySpark kernel has been restarted to use updated packages.\n",
      "\n"
     ]
    }
   ],
   "source": [
    "%pip install \"openai==0.28.1\" \"datasets==2.14.6\" \"diskcache\""
   ]
  },
  {
   "cell_type": "markdown",
   "id": "2",
   "metadata": {},
   "source": [
    "FLAML has provided an API for hyperparameter optimization of OpenAI ChatGPT models: `autogen.ChatCompletion.tune` and to make a request with the tuned config: `autogen.ChatCompletion.create`.\n",
    "First, we import autogen from flaml:"
   ]
  },
  {
   "cell_type": "code",
   "execution_count": null,
   "id": "3",
   "metadata": {
    "slideshow": {
     "slide_type": "slide"
    }
   },
   "outputs": [
    {
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    {
     "name": "stderr",
     "output_type": "stream",
     "text": [
      "2024-09-03 04:36:25.665596: I tensorflow/core/util/port.cc:113] oneDNN custom operations are on. You may see slightly different numerical results due to floating-point round-off errors from different computation orders. To turn them off, set the environment variable `TF_ENABLE_ONEDNN_OPTS=0`.\n",
      "2024-09-03 04:36:25.697355: I tensorflow/core/platform/cpu_feature_guard.cc:182] This TensorFlow binary is optimized to use available CPU instructions in performance-critical operations.\n",
      "To enable the following instructions: SSE4.1 SSE4.2 AVX AVX2 AVX512F AVX512_VNNI FMA, in other operations, rebuild TensorFlow with the appropriate compiler flags.\n"
     ]
    }
   ],
   "source": [
    "from flaml import autogen"
   ]
  },
  {
   "cell_type": "markdown",
   "id": "4",
   "metadata": {},
   "source": [
    "### Set your API Endpoint\n",
    "\n",
    "It's important to note that the built-in [Azure Open AI service](https://learn.microsoft.com/en-us/fabric/data-science/ai-services/ai-services-overview) is not supported on trial SKUs and only paid SKUs (F64 or higher, or P1 or higher) are supported. Please update below config_list with your own LLMs settings.\n"
   ]
  },
  {
   "cell_type": "code",
   "execution_count": null,
   "id": "5",
   "metadata": {},
   "outputs": [
    {
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    },
    {
     "name": "stdout",
     "output_type": "stream",
     "text": [
      "models to use:  ['gpt-35-turbo-0125']\n"
     ]
    }
   ],
   "source": [
    "config_list = [\n",
    "    {\n",
    "        \"model\": \"gpt-35-turbo-0125\",\n",
    "    },\n",
    "]\n",
    "\n",
    "assert len(config_list) > 0\n",
    "print(\"models to use: \", [config_list[i][\"model\"] for i in range(len(config_list))])"
   ]
  },
  {
   "cell_type": "markdown",
   "id": "6",
   "metadata": {
    "nteract": {
     "transient": {
      "deleting": false
     }
    }
   },
   "source": [
    "Check if the configs are valid:"
   ]
  },
  {
   "cell_type": "code",
   "execution_count": null,
   "id": "7",
   "metadata": {
    "jupyter": {
     "outputs_hidden": false,
     "source_hidden": false
    },
    "nteract": {
     "transient": {
      "deleting": false
     }
    }
   },
   "outputs": [
    {
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    {
     "name": "stdout",
     "output_type": "stream",
     "text": [
      "Current model: gpt-35-turbo-0125\n",
      "\u001b[33muser\u001b[0m (to gpt-35-turbo-0125):\n",
      "\n",
      "Tell me a quick joke.\n",
      "\n",
      "--------------------------------------------------------------------------------\n",
      "\u001b[33mgpt-35-turbo-0125\u001b[0m (to user):\n",
      "\n",
      "Why couldn't the bicycle stand up by itself?\n",
      "\n",
      "Because it was two-tired!\n",
      "\n",
      "--------------------------------------------------------------------------------\n"
     ]
    }
   ],
   "source": [
    "for config in config_list:\n",
    "    print(f\"Current model: {config['model']}\")\n",
    "    agent = autogen.agentchat.ConversableAgent(name=config[\"model\"], llm_config={\"config_list\": [config]}, max_consecutive_auto_reply=1, human_input_mode=\"NEVER\")\n",
    "    userproxy = autogen.agentchat.ConversableAgent(name=\"user\", max_consecutive_auto_reply=0, llm_config=False, default_auto_reply=\"TERMINATE\", human_input_mode=\"NEVER\")\n",
    "    userproxy.initiate_chat(recipient=agent, message=\"Tell me a quick joke.\")"
   ]
  },
  {
   "cell_type": "markdown",
   "id": "8",
   "metadata": {},
   "source": [
    "## Load dataset\n",
    "\n",
    "We load the competition_math dataset. The dataset contains 201 \"Level 2\" Algebra examples. We use a random sample of 20 examples for tuning the generation hyperparameters and the remaining for evaluation."
   ]
  },
  {
   "cell_type": "code",
   "execution_count": null,
   "id": "9",
   "metadata": {},
   "outputs": [
    {
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    {
     "name": "stdout",
     "output_type": "stream",
     "text": [
      "20 201\n"
     ]
    }
   ],
   "source": [
    "import datasets\n",
    "\n",
    "seed = 41\n",
    "data = datasets.load_dataset(\"competition_math\")\n",
    "train_data = data[\"train\"].shuffle(seed=seed)\n",
    "test_data = data[\"test\"].shuffle(seed=seed)\n",
    "n_tune_data = 20\n",
    "tune_data = [\n",
    "    {\n",
    "        \"problem\": train_data[x][\"problem\"],\n",
    "        \"solution\": train_data[x][\"solution\"],\n",
    "    }\n",
    "    for x in range(len(train_data))\n",
    "    if train_data[x][\"level\"] == \"Level 2\" and train_data[x][\"type\"] == \"Algebra\"\n",
    "][:n_tune_data]\n",
    "test_data = [\n",
    "    {\n",
    "        \"problem\": test_data[x][\"problem\"],\n",
    "        \"solution\": test_data[x][\"solution\"],\n",
    "    }\n",
    "    for x in range(len(test_data))\n",
    "    if test_data[x][\"level\"] == \"Level 2\" and test_data[x][\"type\"] == \"Algebra\"\n",
    "]\n",
    "print(len(tune_data), len(test_data))"
   ]
  },
  {
   "cell_type": "markdown",
   "id": "10",
   "metadata": {
    "slideshow": {
     "slide_type": "slide"
    }
   },
   "source": [
    "Check a tuning example:"
   ]
  },
  {
   "cell_type": "code",
   "execution_count": null,
   "id": "11",
   "metadata": {
    "slideshow": {
     "slide_type": "subslide"
    },
    "tags": []
   },
   "outputs": [
    {
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     "metadata": {},
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    },
    {
     "name": "stdout",
     "output_type": "stream",
     "text": [
      "If $3+a=4-b$ and $4+b=7+a$, what is $3-a$?\n"
     ]
    }
   ],
   "source": [
    "print(tune_data[1][\"problem\"])"
   ]
  },
  {
   "cell_type": "markdown",
   "id": "12",
   "metadata": {},
   "source": [
    "Here is one example of the canonical solution:"
   ]
  },
  {
   "cell_type": "code",
   "execution_count": null,
   "id": "13",
   "metadata": {},
   "outputs": [
    {
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       "execution_finish_time": "2024-09-03T04:36:35.3766455Z",
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    {
     "name": "stdout",
     "output_type": "stream",
     "text": [
      "First we begin by solving the system of equations \\begin{align*}\n",
      "3+a&=4-b, \\\\\n",
      "4+b&=7+a.\n",
      "\\end{align*}Adding the two equations, we get $3+a+4+b=4-b+7+a$, which simplifies to $7+a+b=11+a-b$. Cancelling $a$ from both sides, we get $7+b=11-b$. Solving for $b$, we find that $b=2$. Plugging this into the first equation above, we obtain $3+a=4-2$. Hence $a=-1$ and $3-a=\\boxed{4}$.\n"
     ]
    }
   ],
   "source": [
    "print(tune_data[1][\"solution\"])"
   ]
  },
  {
   "cell_type": "markdown",
   "id": "14",
   "metadata": {},
   "source": [
    "## Define Success Metric\n",
    "\n",
    "Before we start tuning, we must define the success metric we want to optimize. For each math task, we use voting to select a response with the most common answers out of all the generated responses. We consider the task successfully solved if it has an equivalent answer to the canonical solution. Then we can optimize the mean success rate of a collection of tasks."
   ]
  },
  {
   "cell_type": "code",
   "execution_count": null,
   "id": "15",
   "metadata": {
    "jupyter": {
     "outputs_hidden": false,
     "source_hidden": false
    },
    "nteract": {
     "transient": {
      "deleting": false
     }
    }
   },
   "outputs": [
    {
     "data": {
      "application/vnd.livy.statement-meta+json": {
       "execution_finish_time": "2024-09-03T04:36:36.1245192Z",
       "execution_start_time": "2024-09-03T04:36:35.7665125Z",
       "livy_statement_state": "available",
       "normalized_state": "finished",
       "parent_msg_id": "0e9f9a15-be68-41b1-8718-37bdf0d28494",
       "queued_time": "2024-09-03T04:36:02.0851127Z",
       "session_id": "280727be-3509-4d73-817b-4c3fe9a4d244",
       "session_start_time": null,
       "spark_pool": null,
       "state": "finished",
       "statement_id": 66,
       "statement_ids": [
        66
       ]
      },
      "text/plain": [
       "StatementMeta(, 280727be-3509-4d73-817b-4c3fe9a4d244, 66, Finished, Available, Finished)"
      ]
     },
     "metadata": {},
     "output_type": "display_data"
    }
   ],
   "source": [
    "from flaml.autogen.math_utils import eval_math_responses"
   ]
  },
  {
   "cell_type": "markdown",
   "id": "16",
   "metadata": {
    "slideshow": {
     "slide_type": "slide"
    }
   },
   "source": [
    "## Use the tuning data to find a good configuration\n"
   ]
  },
  {
   "cell_type": "markdown",
   "id": "17",
   "metadata": {},
   "source": [
    "For (local) reproducibility and cost efficiency, we cache responses from OpenAI with a controllable seed."
   ]
  },
  {
   "cell_type": "code",
   "execution_count": null,
   "id": "18",
   "metadata": {
    "slideshow": {
     "slide_type": "slide"
    }
   },
   "outputs": [
    {
     "data": {
      "application/vnd.livy.statement-meta+json": {
       "execution_finish_time": "2024-09-03T04:36:36.8748871Z",
       "execution_start_time": "2024-09-03T04:36:36.5107253Z",
       "livy_statement_state": "available",
       "normalized_state": "finished",
       "parent_msg_id": "03ea8726-7b87-497a-8385-7106ace954b5",
       "queued_time": "2024-09-03T04:36:02.2769006Z",
       "session_id": "280727be-3509-4d73-817b-4c3fe9a4d244",
       "session_start_time": null,
       "spark_pool": null,
       "state": "finished",
       "statement_id": 67,
       "statement_ids": [
        67
       ]
      },
      "text/plain": [
       "StatementMeta(, 280727be-3509-4d73-817b-4c3fe9a4d244, 67, Finished, Available, Finished)"
      ]
     },
     "metadata": {},
     "output_type": "display_data"
    }
   ],
   "source": [
    "autogen.ChatCompletion.set_cache(seed)"
   ]
  },
  {
   "cell_type": "markdown",
   "id": "19",
   "metadata": {},
   "source": [
    "This will create a disk cache in \".cache/{seed}\". You can change `cache_path_root` from \".cache\" to a different path in `set_cache()`. The cache for different seeds are stored separately.\n",
    "\n",
    "### Perform tuning\n",
    "\n",
    "The tuning will take a while to finish, depending on the optimization budget. The tuning will be performed under the specified optimization budgets.\n",
    "\n",
    "* `inference_budget` is the benchmark's target average inference budget per instance. For example, 0.004 means the target inference budget is 0.004 dollars, which translates to 2000 tokens (input + output combined) if the gpt-3.5-turbo model is used.\n",
    "* `optimization_budget` is the total budget allowed for tuning. For example, 1 means 1 dollar is allowed in total, which translates to 500K tokens for the gpt-3.5-turbo model.\n",
    "* `num_sumples` is the number of different hyperparameter configurations allowed to be tried. The tuning will stop after either num_samples trials are completed or optimization_budget dollars are spent, whichever happens first. -1 means no hard restriction in the number of trials and the actual number is decided by `optimization_budget`.\n",
    "\n",
    "Users can specify tuning data, optimization metric, optimization mode, evaluation function, search spaces etc.. The default search space is:\n",
    "\n",
    "```python\n",
    "default_search_space = {\n",
    "    \"model\": tune.choice([\n",
    "        \"gpt-3.5-turbo\",\n",
    "        \"gpt-4\",\n",
    "    ]),\n",
    "    \"temperature_or_top_p\": tune.choice(\n",
    "        [\n",
    "            {\"temperature\": tune.uniform(0, 2)},\n",
    "            {\"top_p\": tune.uniform(0, 1)},\n",
    "        ]\n",
    "    ),\n",
    "    \"max_tokens\": tune.lograndint(50, 1000),\n",
    "    \"n\": tune.randint(1, 100),\n",
    "    \"prompt\": \"{prompt}\",\n",
    "}\n",
    "```\n",
    "\n",
    "The default search space can be overridden by users' input.\n",
    "For example, the following code specifies a fixed prompt template. The default search space will be used for hyperparameters that don't appear in users' input."
   ]
  },
  {
   "cell_type": "code",
   "execution_count": null,
   "id": "20",
   "metadata": {},
   "outputs": [
    {
     "data": {
      "application/vnd.livy.statement-meta+json": {
       "execution_finish_time": "2024-09-03T04:36:37.6159206Z",
       "execution_start_time": "2024-09-03T04:36:37.2611068Z",
       "livy_statement_state": "available",
       "normalized_state": "finished",
       "parent_msg_id": "cd417663-f83a-4d9f-a35d-bb0ba76ad0bb",
       "queued_time": "2024-09-03T04:36:02.4668052Z",
       "session_id": "280727be-3509-4d73-817b-4c3fe9a4d244",
       "session_start_time": null,
       "spark_pool": null,
       "state": "finished",
       "statement_id": 68,
       "statement_ids": [
        68
       ]
      },
      "text/plain": [
       "StatementMeta(, 280727be-3509-4d73-817b-4c3fe9a4d244, 68, Finished, Available, Finished)"
      ]
     },
     "metadata": {},
     "output_type": "display_data"
    }
   ],
   "source": [
    "from flaml import tune\n",
    "\n",
    "models = tune.choice([\"gpt-35-turbo-0125\"])  # to update models to search\n",
    "prompts = [\n",
    "    \"{problem} Solve the problem carefully. Simplify your answer as much as possible. Put the final answer in \\\\boxed{{}}.\"\n",
    "]"
   ]
  },
  {
   "cell_type": "markdown",
   "id": "21",
   "metadata": {
    "nteract": {
     "transient": {
      "deleting": false
     }
    }
   },
   "source": [
    "Since we'll use models which are not pre-defined in FLAML, we can update the models' price info manually. Check [here](https://azure.microsoft.com/en-us/pricing/details/cognitive-services/openai-service/) for more price details."
   ]
  },
  {
   "cell_type": "code",
   "execution_count": null,
   "id": "22",
   "metadata": {
    "jupyter": {
     "outputs_hidden": false,
     "source_hidden": false
    },
    "nteract": {
     "transient": {
      "deleting": false
     }
    }
   },
   "outputs": [
    {
     "data": {
      "application/vnd.livy.statement-meta+json": {
       "execution_finish_time": "2024-09-03T04:36:38.3819827Z",
       "execution_start_time": "2024-09-03T04:36:38.0216811Z",
       "livy_statement_state": "available",
       "normalized_state": "finished",
       "parent_msg_id": "93313823-f851-40a7-b604-9b02a52321cb",
       "queued_time": "2024-09-03T04:36:02.6155812Z",
       "session_id": "280727be-3509-4d73-817b-4c3fe9a4d244",
       "session_start_time": null,
       "spark_pool": null,
       "state": "finished",
       "statement_id": 69,
       "statement_ids": [
        69
       ]
      },
      "text/plain": [
       "StatementMeta(, 280727be-3509-4d73-817b-4c3fe9a4d244, 69, Finished, Available, Finished)"
      ]
     },
     "metadata": {},
     "output_type": "display_data"
    }
   ],
   "source": [
    "autogen.ChatCompletion.chat_models.update({\"gpt-35-turbo-0125\", \"gpt-4o\", \"gpt-4-32k\"})\n",
    "autogen.ChatCompletion.price1K.update({\"gpt-35-turbo-0125\": (0.0005, 0.0015), \"gpt-4o\": (0.005, 0.015), \"gpt-4-32k\": (0.06, 0.12)})"
   ]
  },
  {
   "cell_type": "code",
   "execution_count": null,
   "id": "23",
   "metadata": {
    "jupyter": {
     "outputs_hidden": false,
     "source_hidden": false
    },
    "nteract": {
     "transient": {
      "deleting": false
     }
    }
   },
   "outputs": [
    {
     "data": {
      "application/vnd.livy.statement-meta+json": {
       "execution_finish_time": "2024-09-03T04:42:09.6790767Z",
       "execution_start_time": "2024-09-03T04:36:38.7716495Z",
       "livy_statement_state": "available",
       "normalized_state": "finished",
       "parent_msg_id": "7d9fe157-908c-46d1-b841-f8c35cd45cdd",
       "queued_time": "2024-09-03T04:36:02.7454691Z",
       "session_id": "280727be-3509-4d73-817b-4c3fe9a4d244",
       "session_start_time": null,
       "spark_pool": null,
       "state": "finished",
       "statement_id": 70,
       "statement_ids": [
        70
       ]
      },
      "text/plain": [
       "StatementMeta(, 280727be-3509-4d73-817b-4c3fe9a4d244, 70, Finished, Available, Finished)"
      ]
     },
     "metadata": {},
     "output_type": "display_data"
    },
    {
     "name": "stderr",
     "output_type": "stream",
     "text": [
      "\u001b[32m[I 2024-09-03 04:36:38,702]\u001b[0m A new study created in memory with name: optuna\u001b[0m\n"
     ]
    },
    {
     "name": "stdout",
     "output_type": "stream",
     "text": [
      "No low-cost partial config given to the search algorithm. For cost-frugal search, consider providing low-cost values for cost-related hps via 'low_cost_partial_config'. More info can be found at https://microsoft.github.io/FLAML/docs/FAQ#about-low_cost_partial_config-in-tune\n",
      "[flaml.tune.tune: 09-03 04:36:39] {905} INFO - trial 1 config: {'model': 'gpt-35-turbo-0125', 'temperature_or_top_p': {'top_p': 0.36280922847807595}, 'max_tokens': 347, 'n': 10, 'prompt': 0, 'allow_format_str_template': True}\n",
      "[flaml.tune.tune: 09-03 04:37:38] {909} DEBUG - result in tune: <flaml.tune.trial_runner.SimpleTrial object at 0x7305ab2ab290>, {'expected_success': 0.9150833227400001, 'success': 0.95, 'success_vote': 0.85, 'voted_answer': 'We can see that each term in the sequence is obtained by dividing the previous term by 3. \\n\\nSo, the sequence can be written as $6075, \\\\frac{6075}{3}, \\\\frac{6075}{3^2}, \\\\frac{6075}{3^3}, \\\\ldots$\\n\\nThe $n$th term in the sequence is given by $a_n = \\\\frac{6075}{3^{n-1}}$\\n\\nWe want to find the number of integers in this sequence. For a term to be an integer, the denominator $3^{n-1}$ must divide 6075 evenly.\\n\\n6075 can be expressed as $3^3 \\\\cdot 5^2 \\\\cdot 9$. \\n\\nSo, the divisors of 6075 are of the form $3^a \\\\cdot 5^b \\\\cdot 9^c$, where $0 \\\\leq a \\\\leq 3$, $0 \\\\leq b \\\\leq 2$, and $0 \\\\leq c \\\\leq 1$.\\n\\nSince $3^{n-1}$ must be a divisor of 6075, $n-1$ must be less than or equal to 3. So, $n$ can take on the values 1, 2, 3, 4.\\n\\nTherefore, there are $\\\\boxed{4}$ integers in this sequence.', 'votes': 9.2, 'total_cost': 0.06967800000000003, 'cost': 0.06967800000000003, 'inference_cost': 0.002280175}\n",
      "[flaml.tune.tune: 09-03 04:37:38] {242} INFO - result: {'expected_success': 0.9150833227400001, 'success': 0.95, 'success_vote': 0.85, 'voted_answer': 'We can see that each term in the sequence is obtained by dividing the previous term by 3. \\n\\nSo, the sequence can be written as $6075, \\\\frac{6075}{3}, \\\\frac{6075}{3^2}, \\\\frac{6075}{3^3}, \\\\ldots$\\n\\nThe $n$th term in the sequence is given by $a_n = \\\\frac{6075}{3^{n-1}}$\\n\\nWe want to find the number of integers in this sequence. For a term to be an integer, the denominator $3^{n-1}$ must divide 6075 evenly.\\n\\n6075 can be expressed as $3^3 \\\\cdot 5^2 \\\\cdot 9$. \\n\\nSo, the divisors of 6075 are of the form $3^a \\\\cdot 5^b \\\\cdot 9^c$, where $0 \\\\leq a \\\\leq 3$, $0 \\\\leq b \\\\leq 2$, and $0 \\\\leq c \\\\leq 1$.\\n\\nSince $3^{n-1}$ must be a divisor of 6075, $n-1$ must be less than or equal to 3. So, $n$ can take on the values 1, 2, 3, 4.\\n\\nTherefore, there are $\\\\boxed{4}$ integers in this sequence.', 'votes': 9.2, 'total_cost': 0.06967800000000003, 'cost': 0.06967800000000003, 'inference_cost': 0.002280175, 'training_iteration': 0, 'config': {'model': 'gpt-35-turbo-0125', 'temperature_or_top_p': {'top_p': 0.36280922847807595}, 'max_tokens': 347, 'n': 10, 'prompt': 0, 'allow_format_str_template': True}, 'config/model': 'gpt-35-turbo-0125', 'config/temperature_or_top_p': {'top_p': 0.36280922847807595}, 'config/max_tokens': 347, 'config/n': 10, 'config/prompt': 0, 'config/allow_format_str_template': True, 'experiment_tag': 'exp', 'time_total_s': 58.405787229537964}\n",
      "[flaml.tune.tune: 09-03 04:37:38] {905} INFO - trial 2 config: {'model': 'gpt-35-turbo-0125', 'temperature_or_top_p': {'temperature': 1.2672964698525508}, 'max_tokens': 470, 'n': 50, 'prompt': 0, 'allow_format_str_template': True}\n",
      "[flaml.tune.tune: 09-03 04:39:14] {909} DEBUG - result in tune: <flaml.tune.trial_runner.SimpleTrial object at 0x73058060b890>, {'expected_success': 0.9817914610756876, 'success': 1.0, 'success_vote': 0.9, 'voted_answer': \"First, let's see if we can find a pattern in the exponents of 3 as we go from one number to the next.\\n\\nStarting with 6075, which is $3^5 \\\\cdot 5$, we divide by 3 to get 2025, which is $3^4 \\\\cdot 5$. From 2025 to 675, we are dividing by 3 again, and we get $3^3 \\\\cdot 5$. \\n\\nSo, we can see that each time we are dividing by 3, the exponent of 3 is decreasing by 1.\\n\\nContinuing this pattern, the next number in the sequence would be $3^2 \\\\cdot 5$, then $3^1 \\\\cdot 5$, and finally $3^0 \\\\cdot 5$. \\n\\nSo, there are a total of 6 integers in this sequence - 6075, 2025, 675, 225, 75, and 25. \\n\\nTherefore, the final answer is $\\\\boxed{6}$.\", 'votes': 39.85, 'total_cost': 0.39890600000000004, 'cost': 0.329228, 'inference_cost': 0.011811775}\n",
      "[flaml.tune.tune: 09-03 04:39:14] {242} INFO - result: {'expected_success': 0.9817914610756876, 'success': 1.0, 'success_vote': 0.9, 'voted_answer': \"First, let's see if we can find a pattern in the exponents of 3 as we go from one number to the next.\\n\\nStarting with 6075, which is $3^5 \\\\cdot 5$, we divide by 3 to get 2025, which is $3^4 \\\\cdot 5$. From 2025 to 675, we are dividing by 3 again, and we get $3^3 \\\\cdot 5$. \\n\\nSo, we can see that each time we are dividing by 3, the exponent of 3 is decreasing by 1.\\n\\nContinuing this pattern, the next number in the sequence would be $3^2 \\\\cdot 5$, then $3^1 \\\\cdot 5$, and finally $3^0 \\\\cdot 5$. \\n\\nSo, there are a total of 6 integers in this sequence - 6075, 2025, 675, 225, 75, and 25. \\n\\nTherefore, the final answer is $\\\\boxed{6}$.\", 'votes': 39.85, 'total_cost': 0.39890600000000004, 'cost': 0.329228, 'inference_cost': 0.011811775, 'training_iteration': 0, 'config': {'model': 'gpt-35-turbo-0125', 'temperature_or_top_p': {'temperature': 1.2672964698525508}, 'max_tokens': 470, 'n': 50, 'prompt': 0, 'allow_format_str_template': True}, 'config/model': 'gpt-35-turbo-0125', 'config/temperature_or_top_p': {'temperature': 1.2672964698525508}, 'config/max_tokens': 470, 'config/n': 50, 'config/prompt': 0, 'config/allow_format_str_template': True, 'experiment_tag': 'exp', 'time_total_s': 95.78834676742554}\n",
      "[flaml.tune.tune: 09-03 04:39:14] {905} INFO - trial 3 config: {'model': 'gpt-35-turbo-0125', 'temperature_or_top_p': {'temperature': 1.5210614243979175}, 'max_tokens': 82, 'n': 9, 'prompt': 0, 'allow_format_str_template': True}\n",
      "[flaml.tune.tune: 09-03 04:39:35] {909} DEBUG - result in tune: <flaml.tune.trial_runner.SimpleTrial object at 0x730580e22690>, {'expected_success': 0.11405544364485072, 'success': 0.15, 'success_vote': 0.15, 'voted_answer': 'Since we are repeatedly dividing by 3, the next number in the sequence after $675$ is $\\\\frac{675}{3} = 225$. Similarly, the next number after $225$ is $\\\\frac{225}{3} = 75$, and after $75$ is $\\\\frac{75}{3} = 25$. Continuing this pattern, the next numbers in the sequence are $\\\\frac', 'votes': 0.35, 'total_cost': 0.4307120000000001, 'cost': 0.031806, 'inference_cost': 0.001132225}\n",
      "[flaml.tune.tune: 09-03 04:39:35] {242} INFO - result: {'expected_success': 0.11405544364485072, 'success': 0.15, 'success_vote': 0.15, 'voted_answer': 'Since we are repeatedly dividing by 3, the next number in the sequence after $675$ is $\\\\frac{675}{3} = 225$. Similarly, the next number after $225$ is $\\\\frac{225}{3} = 75$, and after $75$ is $\\\\frac{75}{3} = 25$. Continuing this pattern, the next numbers in the sequence are $\\\\frac', 'votes': 0.35, 'total_cost': 0.4307120000000001, 'cost': 0.031806, 'inference_cost': 0.001132225, 'training_iteration': 0, 'config': {'model': 'gpt-35-turbo-0125', 'temperature_or_top_p': {'temperature': 1.5210614243979175}, 'max_tokens': 82, 'n': 9, 'prompt': 0, 'allow_format_str_template': True}, 'config/model': 'gpt-35-turbo-0125', 'config/temperature_or_top_p': {'temperature': 1.5210614243979175}, 'config/max_tokens': 82, 'config/n': 9, 'config/prompt': 0, 'config/allow_format_str_template': True, 'experiment_tag': 'exp', 'time_total_s': 21.19859290122986}\n",
      "[flaml.tune.tune: 09-03 04:39:35] {905} INFO - trial 4 config: {'model': 'gpt-35-turbo-0125', 'temperature_or_top_p': {'top_p': 0.003948266327914451}, 'max_tokens': 231, 'n': 81, 'prompt': 0, 'allow_format_str_template': True}\n",
      "[flaml.tune.tune: 09-03 04:41:42] {909} DEBUG - result in tune: <flaml.tune.trial_runner.SimpleTrial object at 0x730580587390>, {'expected_success': 0.9, 'success': 0.9, 'success_vote': 0.85, 'voted_answer': 'We can see that each term in the sequence is obtained by dividing the previous term by 3. \\n\\nSo, the terms in the sequence are $6075, 2025, 675, 225, 75, 25, 8.\\\\overline{3}, 2.\\\\overline{7}, 0.\\\\overline{9}$, and so on.\\n\\nWe can see that the sequence stops at $0.\\\\overline{9}$, as the next term would be $0.\\\\overline{3}$ which is not an integer.\\n\\nTherefore, there are $\\\\boxed{9}$ integers in this sequence.', 'votes': 72.1, 'total_cost': 0.9328879999999999, 'cost': 0.5021760000000002, 'inference_cost': 0.0182209}\n",
      "[flaml.tune.tune: 09-03 04:41:42] {242} INFO - result: {'expected_success': 0.9, 'success': 0.9, 'success_vote': 0.85, 'voted_answer': 'We can see that each term in the sequence is obtained by dividing the previous term by 3. \\n\\nSo, the terms in the sequence are $6075, 2025, 675, 225, 75, 25, 8.\\\\overline{3}, 2.\\\\overline{7}, 0.\\\\overline{9}$, and so on.\\n\\nWe can see that the sequence stops at $0.\\\\overline{9}$, as the next term would be $0.\\\\overline{3}$ which is not an integer.\\n\\nTherefore, there are $\\\\boxed{9}$ integers in this sequence.', 'votes': 72.1, 'total_cost': 0.9328879999999999, 'cost': 0.5021760000000002, 'inference_cost': 0.0182209, 'training_iteration': 0, 'config': {'model': 'gpt-35-turbo-0125', 'temperature_or_top_p': {'top_p': 0.003948266327914451}, 'max_tokens': 231, 'n': 81, 'prompt': 0, 'allow_format_str_template': True}, 'config/model': 'gpt-35-turbo-0125', 'config/temperature_or_top_p': {'top_p': 0.003948266327914451}, 'config/max_tokens': 231, 'config/n': 81, 'config/prompt': 0, 'config/allow_format_str_template': True, 'experiment_tag': 'exp', 'time_total_s': 126.93746018409729}\n",
      "[flaml.tune.tune: 09-03 04:41:42] {905} INFO - trial 5 config: {'model': 'gpt-35-turbo-0125', 'temperature_or_top_p': {'top_p': 0.29187606817063316}, 'max_tokens': 781, 'n': 71, 'prompt': 0, 'allow_format_str_template': True}\n",
      "[flaml.tune.tune: 09-03 04:42:05] {909} DEBUG - result in tune: <flaml.tune.trial_runner.SimpleTrial object at 0x730580dd8fd0>, {'success_vote': 0, 'total_cost': 1.011984, 'cost': 0.079096}\n",
      "[flaml.tune.tune: 09-03 04:42:05] {242} INFO - result: {'success_vote': 0, 'total_cost': 1.011984, 'cost': 0.079096, 'training_iteration': 0, 'config': {'model': 'gpt-35-turbo-0125', 'temperature_or_top_p': {'top_p': 0.29187606817063316}, 'max_tokens': 781, 'n': 71, 'prompt': 0, 'allow_format_str_template': True}, 'config/model': 'gpt-35-turbo-0125', 'config/temperature_or_top_p': {'top_p': 0.29187606817063316}, 'config/max_tokens': 781, 'config/n': 71, 'config/prompt': 0, 'config/allow_format_str_template': True, 'experiment_tag': 'exp', 'time_total_s': 22.84635353088379}\n",
      "[flaml.tune.tune: 09-03 04:42:05] {932} WARNING - fail to sample a trial for 100 times in a row, stopping.\n"
     ]
    }
   ],
   "source": [
    "import logging\n",
    "\n",
    "config, analysis = autogen.ChatCompletion.tune(\n",
    "    data=tune_data,  # the data for tuning\n",
    "    metric=\"success_vote\",  # the metric to optimize\n",
    "    mode=\"max\",  # the optimization mode\n",
    "    eval_func=eval_math_responses,  # the evaluation function to return the success metrics\n",
    "    # log_file_name=\"logs/math.log\",  # the log file name\n",
    "    inference_budget=0.02,  # the inference budget (dollar per instance)\n",
    "    optimization_budget=1,  # the optimization budget (dollar in total)\n",
    "    # num_samples can further limit the number of trials for different hyperparameter configurations;\n",
    "    # -1 means decided by the optimization budget only\n",
    "    num_samples=20,  # number of configurations to try\n",
    "    prompt=prompts,  # the prompt templates to choose from\n",
    "    # stop=\"###\",  # the stop sequence\n",
    "    config_list=config_list,  # the endpoint list\n",
    "    allow_format_str_template=True,  # whether to allow format string template\n",
    "    logging_level=logging.INFO,  # the logging level\n",
    "    model=models,  # models to choose from\n",
    ")"
   ]
  },
  {
   "cell_type": "markdown",
   "id": "24",
   "metadata": {},
   "source": [
    "### Output tuning results\n",
    "\n",
    "After the tuning, we can print out the config and the result found by FLAML:"
   ]
  },
  {
   "cell_type": "code",
   "execution_count": null,
   "id": "25",
   "metadata": {},
   "outputs": [
    {
     "data": {
      "application/vnd.livy.statement-meta+json": {
       "execution_finish_time": "2024-09-03T04:42:10.4284007Z",
       "execution_start_time": "2024-09-03T04:42:10.078259Z",
       "livy_statement_state": "available",
       "normalized_state": "finished",
       "parent_msg_id": "4503b3d1-7c5a-4177-8109-c430174ee5b3",
       "queued_time": "2024-09-03T04:36:02.9235543Z",
       "session_id": "280727be-3509-4d73-817b-4c3fe9a4d244",
       "session_start_time": null,
       "spark_pool": null,
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       "statement_id": 71,
       "statement_ids": [
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     "metadata": {},
     "output_type": "display_data"
    },
    {
     "name": "stdout",
     "output_type": "stream",
     "text": [
      "optimized config {'model': 'gpt-35-turbo-0125', 'max_tokens': 470, 'n': 50, 'prompt': '{problem} Solve the problem carefully. Simplify your answer as much as possible. Put the final answer in \\\\boxed{{}}.', 'allow_format_str_template': True, 'temperature': 1.2672964698525508}\n",
      "best result on tuning data {'expected_success': 0.9817914610756876, 'success': 1.0, 'success_vote': 0.9, 'voted_answer': \"First, let's see if we can find a pattern in the exponents of 3 as we go from one number to the next.\\n\\nStarting with 6075, which is $3^5 \\\\cdot 5$, we divide by 3 to get 2025, which is $3^4 \\\\cdot 5$. From 2025 to 675, we are dividing by 3 again, and we get $3^3 \\\\cdot 5$. \\n\\nSo, we can see that each time we are dividing by 3, the exponent of 3 is decreasing by 1.\\n\\nContinuing this pattern, the next number in the sequence would be $3^2 \\\\cdot 5$, then $3^1 \\\\cdot 5$, and finally $3^0 \\\\cdot 5$. \\n\\nSo, there are a total of 6 integers in this sequence - 6075, 2025, 675, 225, 75, and 25. \\n\\nTherefore, the final answer is $\\\\boxed{6}$.\", 'votes': 39.85, 'total_cost': 0.39890600000000004, 'cost': 0.329228, 'inference_cost': 0.011811775, 'training_iteration': 0, 'config': {'model': 'gpt-35-turbo-0125', 'temperature_or_top_p': {'temperature': 1.2672964698525508}, 'max_tokens': 470, 'n': 50, 'prompt': 0, 'allow_format_str_template': True}, 'config/model': 'gpt-35-turbo-0125', 'config/temperature_or_top_p': {'temperature': 1.2672964698525508}, 'config/max_tokens': 470, 'config/n': 50, 'config/prompt': 0, 'config/allow_format_str_template': True, 'experiment_tag': 'exp', 'time_total_s': 95.78834676742554}\n"
     ]
    }
   ],
   "source": [
    "print(\"optimized config\", config)\n",
    "print(\"best result on tuning data\", analysis.best_result)"
   ]
  },
  {
   "cell_type": "markdown",
   "id": "26",
   "metadata": {
    "slideshow": {
     "slide_type": "slide"
    }
   },
   "source": [
    "### Make a request with the tuned config\n",
    "\n",
    "We can apply the tuned config on the request for an example task:"
   ]
  },
  {
   "cell_type": "code",
   "execution_count": null,
   "id": "27",
   "metadata": {
    "slideshow": {
     "slide_type": "subslide"
    },
    "tags": []
   },
   "outputs": [
    {
     "data": {
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       "queued_time": "2024-09-03T04:36:03.0423953Z",
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       "session_start_time": null,
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    },
    {
     "name": "stdout",
     "output_type": "stream",
     "text": [
      "response on an example data instance: {\n",
      "  \"id\": \"chatcmpl-A3FaYDpLh5cHf8tL5FvDGm2Kp2NKb\",\n",
      "  \"choices\": [\n",
      "    {\n",
      "      \"content_filter_results\": {\n",
      "        \"hate\": {\n",
      "          \"filtered\": false,\n",
      "          \"severity\": \"safe\"\n",
      "        },\n",
      "        \"self_harm\": {\n",
      "          \"filtered\": false,\n",
      "          \"severity\": \"safe\"\n",
      "        },\n",
      "        \"sexual\": {\n",
      "          \"filtered\": false,\n",
      "          \"severity\": \"safe\"\n",
      "        },\n",
      "        \"violence\": {\n",
      "          \"filtered\": false,\n",
      "          \"severity\": \"safe\"\n",
      "        }\n",
      "      },\n",
      "      \"finish_reason\": \"stop\",\n",
      "      \"index\": 0,\n",
      "      \"message\": {\n",
      "        \"content\": \"Given:\\n$3+a=4-b$ ...(1)\\n$4+b=7+a$ ...(2)\\n\\nCombining equations (1) and (2) to isolate $a$ and $b$:\\n\\n$3+a = 4-b \\\\implies a+b = 1$ ...(3)\\n$4+b = 7+a \\\\implies b-a = 3$ ...(4)\\n\\nAdding equations (3) and (4) gives:\\n$(a+b) + (b-a) = 1+3$\\n$2b = 4$\\n$b = 2$\\n\\nSubstitute $b=2$ into equation (3) gives:\\n$a+2 = 1 \\\\implies a = -1$\\n\\nNow that we have found the values of $a$ and $b$, we can find $3-a$:\\n\\n$3-a = 3 - (-1) = 3 + 1 = 4$\\n\\nTherefore, $\\\\boxed{4}$ is the value of $3-a$.\",\n",
      "        \"role\": \"assistant\"\n",
      "      }\n",
      "    },\n",
      "    {\n",
      "      \"content_filter_results\": {\n",
      "        \"hate\": {\n",
      "          \"filtered\": false,\n",
      "          \"severity\": \"safe\"\n",
      "        },\n",
      "        \"self_harm\": {\n",
      "          \"filtered\": false,\n",
      "          \"severity\": \"safe\"\n",
      "        },\n",
      "        \"sexual\": {\n",
      "          \"filtered\": false,\n",
      "          \"severity\": \"safe\"\n",
      "        },\n",
      "        \"violence\": {\n",
      "          \"filtered\": false,\n",
      "          \"severity\": \"safe\"\n",
      "        }\n",
      "      },\n",
      "      \"finish_reason\": \"stop\",\n",
      "      \"index\": 1,\n",
      "      \"message\": {\n",
      "        \"content\": \"First, since $3+a=4-b$, we can rearrange this equation to get $a=-1+b$.\\nThen, plug this value of $a$ into the second equation $4+b=7+a$:\\n$4+b=7+(-1+b)$\\n$4+b=6+b$\\n$b=b$\\nTherefore, we find that $b$ can be any real number.\\n\\nNow, let's find $a$ in terms of $b$ from the found relationship. $a=-1+b$\\nNow plug that into $3-a$:\\n$3-a=3-(-1+b)=3+1-b=4-b$\\n\\nTherefore, whatever the value of $b$ is, $3-a=4-b$.\\n\\n$$\\\\boxed{4-b}$$\",\n",
      "        \"role\": \"assistant\"\n",
      "      }\n",
      "    },\n",
      "    {\n",
      "      \"content_filter_results\": {\n",
      "        \"hate\": {\n",
      "          \"filtered\": false,\n",
      "          \"severity\": \"safe\"\n",
      "        },\n",
      "        \"self_harm\": {\n",
      "          \"filtered\": false,\n",
      "          \"severity\": \"safe\"\n",
      "        },\n",
      "        \"sexual\": {\n",
      "          \"filtered\": false,\n",
      "          \"severity\": \"safe\"\n",
      "        },\n",
      "        \"violence\": {\n",
      "          \"filtered\": false,\n",
      "          \"severity\": \"safe\"\n",
      "        }\n",
      "      },\n",
      "      \"finish_reason\": \"stop\",\n",
      "      \"index\": 2,\n",
      "      \"message\": {\n",
      "        \"content\": \"First, let's solve the two equations simultaneously.\\n\\nFrom the first equation $3+a=4-b$, we can rewrite it as $a+b=1$.\\n\\nSimilarly, from the second equation $4+b=7+a$, we can rewrite it as $a-b=3$.\\n\\nNow, we have the system of equations:\\n$a+b=1$ \\n$a-b=3$\\n\\nAdding the two equations together, we get:\\n$2a = 4$\\n$a=2$\\n\\nPlugging $a=2$ back into $a+b=1$, we find:\\n$2+b=1$\\n$b=-1$\\n\\nNow, solving for $3-a$:\\n$3-a = 3-2 = 1$\\n\\nTherefore, $\\\\boxed{1}$ is the final answer.\",\n",
      "        \"role\": \"assistant\"\n",
      "      }\n",
      "    },\n",
      "    {\n",
      "      \"content_filter_results\": {\n",
      "        \"hate\": {\n",
      "          \"filtered\": false,\n",
      "          \"severity\": \"safe\"\n",
      "        },\n",
      "        \"self_harm\": {\n",
      "          \"filtered\": false,\n",
      "          \"severity\": \"safe\"\n",
      "        },\n",
      "        \"sexual\": {\n",
      "          \"filtered\": false,\n",
      "          \"severity\": \"safe\"\n",
      "        },\n",
      "        \"violence\": {\n",
      "          \"filtered\": false,\n",
      "          \"severity\": \"safe\"\n",
      "        }\n",
      "      },\n",
      "      \"finish_reason\": \"stop\",\n",
      "      \"index\": 3,\n",
      "      \"message\": {\n",
      "        \"content\": \"Let's first solve for $a$ and $b$ separately by manipulating the equations given:\\n\\nFrom the first equation, $3+a=4-b$, we can rearrange it to get $a=-1-b$.\\n\\nNext, substitute $a=-1-b$ into the second equation, $4+b=7+a$, we get $4+b=7+(-1-b)$:\\n$4+b=6-b$,\\n$2b=2$,\\n$b=1$.\\n\\nNow, substitute $b=1$ into $a=-1-b$, we get $a=-1-1$:\\n$a=-2$.\\n\\nFinally, we can find $3-a$:\\n$3-(-2)=3+2=\\\\boxed{5}$.\\n\\nTherefore, $3-a$ is equal to 5.\",\n",
      "        \"role\": \"assistant\"\n",
      "      }\n",
      "    },\n",
      "    {\n",
      "      \"content_filter_results\": {\n",
      "        \"hate\": {\n",
      "          \"filtered\": false,\n",
      "          \"severity\": \"safe\"\n",
      "        },\n",
      "        \"self_harm\": {\n",
      "          \"filtered\": false,\n",
      "          \"severity\": \"safe\"\n",
      "        },\n",
      "        \"sexual\": {\n",
      "          \"filtered\": false,\n",
      "          \"severity\": \"safe\"\n",
      "        },\n",
      "        \"violence\": {\n",
      "          \"filtered\": false,\n",
      "          \"severity\": \"safe\"\n",
      "        }\n",
      "      },\n",
      "      \"finish_reason\": \"stop\",\n",
      "      \"index\": 4,\n",
      "      \"message\": {\n",
      "        \"content\": \"Adding the two equations, we get:\\n\\n$(3+a)+(4+b) = (4-b)+(7+a)$\\n$7+(a+b) = 11+(a-b)$\\n$a+b = a-b+4$\\n\\nBringing like terms together, we get:\\n\\n$2b = 4$\\n$b = 2$\\n\\nSubstitute $b=2$ back into the first equation:\\n\\n$3+a = 4-2$\\n$3+a=2$\\n$a=-1$\\n\\nFinally, find $3-a$:\\n\\n$3-(-1) = 3+1 = 4$\\n\\nTherefore, $\\\\boxed{4}$ is the final answer.\",\n",
      "        \"role\": \"assistant\"\n",
      "      }\n",
      "    },\n",
      "    {\n",
      "      \"content_filter_results\": {\n",
      "        \"hate\": {\n",
      "          \"filtered\": false,\n",
      "          \"severity\": \"safe\"\n",
      "        },\n",
      "        \"self_harm\": {\n",
      "          \"filtered\": false,\n",
      "          \"severity\": \"safe\"\n",
      "        },\n",
      "        \"sexual\": {\n",
      "          \"filtered\": false,\n",
      "          \"severity\": \"safe\"\n",
      "        },\n",
      "        \"violence\": {\n",
      "          \"filtered\": false,\n",
      "          \"severity\": \"safe\"\n",
      "        }\n",
      "      },\n",
      "      \"finish_reason\": \"stop\",\n",
      "      \"index\": 5,\n",
      "      \"message\": {\n",
      "        \"content\": \"Let's simplify the given equations one at a time:\\n\\n1. $3 + a = 4 - b$\\n\\nRearranging the equation, we get:\\n\\n$a = 1 - b$\\n\\n2. $4 + b = 7 +a$\\n\\nRearranging the equation, we get:\\n\\n$b = 3 + a$\\n\\nNow, substituting the value of $a$ from the first equation into the second equation:\\n\\n$b = 3 + (1 - b)$\\n\\n$b = 4 - b$\\n\\n$2b = 4$\\n\\n$b = 2$\\n\\nSubstitute this back into the first equation to find $a$:\\n\\n$a = 1 - 2$\\n\\n$a = -1$\\n\\nNow, we can calculate what $3 - a$ is:\\n\\n$3 - a = 3 - (-1) = 3 + 1 = 4$\\n\\nTherefore, $3 - a = \\\\boxed{4}$.\",\n",
      "        \"role\": \"assistant\"\n",
      "      }\n",
      "    },\n",
      "    {\n",
      "      \"content_filter_results\": {\n",
      "        \"hate\": {\n",
      "          \"filtered\": false,\n",
      "          \"severity\": \"safe\"\n",
      "        },\n",
      "        \"self_harm\": {\n",
      "          \"filtered\": false,\n",
      "          \"severity\": \"safe\"\n",
      "        },\n",
      "        \"sexual\": {\n",
      "          \"filtered\": false,\n",
      "          \"severity\": \"safe\"\n",
      "        },\n",
      "        \"violence\": {\n",
      "          \"filtered\": false,\n",
      "          \"severity\": \"safe\"\n",
      "        }\n",
      "      },\n",
      "      \"finish_reason\": \"stop\",\n",
      "      \"index\": 6,\n",
      "      \"message\": {\n",
      "        \"content\": \"Given equations:\\n\\n$3+a=4-b$\\n\\n$4+b=7+a$\\n\\nRearranging the equations, we get:\\n\\n$a+b=1$\\n\\n$a-b=3$ (Obtained by subtracting the first equation from the second)\\n\\nAdding the above two equations:\\n\\n$2a=\\\\boxed{4}$\\n\\nTherefore, the value of $3-a$ is $\\\\boxed{4}$.\",\n",
      "        \"role\": \"assistant\"\n",
      "      }\n",
      "    },\n",
      "    {\n",
      "      \"content_filter_results\": {\n",
      "        \"hate\": {\n",
      "          \"filtered\": false,\n",
      "          \"severity\": \"safe\"\n",
      "        },\n",
      "        \"self_harm\": {\n",
      "          \"filtered\": false,\n",
      "          \"severity\": \"safe\"\n",
      "        },\n",
      "        \"sexual\": {\n",
      "          \"filtered\": false,\n",
      "          \"severity\": \"safe\"\n",
      "        },\n",
      "        \"violence\": {\n",
      "          \"filtered\": false,\n",
      "          \"severity\": \"safe\"\n",
      "        }\n",
      "      },\n",
      "      \"finish_reason\": \"stop\",\n",
      "      \"index\": 7,\n",
      "      \"message\": {\n",
      "        \"content\": \"Given that $3+a=4-b$ and $4+b=7+a$, we can solve these two equations simultaneously.\\n\\nFrom the first equation, we have: $b=4-3-a \\\\Rightarrow b=1-a$\\nSubstitute $b$ in the second equation: $4+(1-a)=7+a$\\n$5-a=7+a$\\n$5=7+2a$\\n$2a=-2$\\n$a=-1$\\nSubstitute $a=-1$ into $b=1-a$, we get: $b=1-(-1) \\\\Rightarrow b=2$ \\n\\nTherefore, $3-a = 3-(-1)=3+1=4$\\n\\nHence, $\\\\boxed{4}$ is the answer.\",\n",
      "        \"role\": \"assistant\"\n",
      "      }\n",
      "    },\n",
      "    {\n",
      "      \"content_filter_results\": {\n",
      "        \"hate\": {\n",
      "          \"filtered\": false,\n",
      "          \"severity\": \"safe\"\n",
      "        },\n",
      "        \"self_harm\": {\n",
      "          \"filtered\": false,\n",
      "          \"severity\": \"safe\"\n",
      "        },\n",
      "        \"sexual\": {\n",
      "          \"filtered\": false,\n",
      "          \"severity\": \"safe\"\n",
      "        },\n",
      "        \"violence\": {\n",
      "          \"filtered\": false,\n",
      "          \"severity\": \"safe\"\n",
      "        }\n",
      "      },\n",
      "      \"finish_reason\": \"stop\",\n",
      "      \"index\": 8,\n",
      "      \"message\": {\n",
      "        \"content\": \"Given the equations $3+a=4-b$ and $4+b=7+a$, we can rearrange the equations to isolate $b$:\\n\\nFrom $3+a=4-b$:\\n$b = 4 - (3+a)$\\n$b = 4 - 3 - a$\\n$b = 1 - a$\\n\\n\\nFrom $4+b=7+a$:\\n$b = 7+a - 4$\\n$b = 3+a$\\n\\nSetting $1-a = 3+a$, we get:\\n\\n$1-a = 3+a$\\n\\n$1 = 3+2a$\\n\\n$2a = 1-3$\\n\\n$2a = -2$\\n\\n$a = -1$\\n\\nNow, substitute $a=-1$ into the equation $b = 1 - a$:\\n\\n$b = 1 - (-1)$\\n$b = 1 + 1$\\n$b = 2$\\n\\nFinally, find $3-a$:\\n\\n$3 - (-1)$\\n$3 + 1$\\n$4$\\n\\nTherefore, $3-a = 4$, and $\\\\boxed{4}$ is the final answer.\",\n",
      "        \"role\": \"assistant\"\n",
      "      }\n",
      "    },\n",
      "    {\n",
      "      \"content_filter_results\": {\n",
      "        \"hate\": {\n",
      "          \"filtered\": false,\n",
      "          \"severity\": \"safe\"\n",
      "        },\n",
      "        \"self_harm\": {\n",
      "          \"filtered\": false,\n",
      "          \"severity\": \"safe\"\n",
      "        },\n",
      "        \"sexual\": {\n",
      "          \"filtered\": false,\n",
      "          \"severity\": \"safe\"\n",
      "        },\n",
      "        \"violence\": {\n",
      "          \"filtered\": false,\n",
      "          \"severity\": \"safe\"\n",
      "        }\n",
      "      },\n",
      "      \"finish_reason\": \"stop\",\n",
      "      \"index\": 9,\n",
      "      \"message\": {\n",
      "        \"content\": \"Starting with the first equation, we have $3+a=4-b$. Rearranging this equation, we get $a=-1+b$.\\n\\nSubstitute this value of $a$ into the second equation $4+b=7+a$:\\n\\n$4+b=7+(-1+b)$\\n\\n$4+b=6+b$\\n\\nSubtracting $b$ from both sides gives us:\\n\\n$4=6$\\n\\nThis is a contradiction, which means there are no real solutions to this system of equations.\\n\\nTherefore, $3-a$ is undefined. \\n\\n\\\\boxed{\\\\text{Undefined}}\",\n",
      "        \"role\": \"assistant\"\n",
      "      }\n",
      "    },\n",
      "    {\n",
      "      \"content_filter_results\": {\n",
      "        \"hate\": {\n",
      "          \"filtered\": false,\n",
      "          \"severity\": \"safe\"\n",
      "        },\n",
      "        \"self_harm\": {\n",
      "          \"filtered\": false,\n",
      "          \"severity\": \"safe\"\n",
      "        },\n",
      "        \"sexual\": {\n",
      "          \"filtered\": false,\n",
      "          \"severity\": \"safe\"\n",
      "        },\n",
      "        \"violence\": {\n",
      "          \"filtered\": false,\n",
      "          \"severity\": \"safe\"\n",
      "        }\n",
      "      },\n",
      "      \"finish_reason\": \"stop\",\n",
      "      \"index\": 10,\n",
      "      \"message\": {\n",
      "        \"content\": \"From the first equation, let's isolate $a$:\\n\\n$3 + a = 4 - b$\\n$a = 1 - b$\\n\\nNow, substitute $a = 1 - b$ in the second equation:\\n\\n$4 + b = 7 + a$\\n$4 + b = 7 + (1 - b)$\\n$4 + b = 8 - b$\\n\\nNow, let's isolate $b$ in this equation:\\n\\n$4 + b = 8 - b$\\n$2b = 4$\\n$b = 2$\\n\\nNow substitute $b = 2$ back into $a = 1 - b$ to find $a$:\\n\\n$a = 1 - 2$\\n$a = -1$\\n\\nFinally, find $3 - a$ given $a = -1$:\\n\\n$3 - (-1)$\\n$3 + 1$\\n$4$\\n\\nTherefore, $\\\\boxed{4}$ is the final answer.\",\n",
      "        \"role\": \"assistant\"\n",
      "      }\n",
      "    },\n",
      "    {\n",
      "      \"content_filter_results\": {\n",
      "        \"hate\": {\n",
      "          \"filtered\": false,\n",
      "          \"severity\": \"safe\"\n",
      "        },\n",
      "        \"self_harm\": {\n",
      "          \"filtered\": false,\n",
      "          \"severity\": \"safe\"\n",
      "        },\n",
      "        \"sexual\": {\n",
      "          \"filtered\": false,\n",
      "          \"severity\": \"safe\"\n",
      "        },\n",
      "        \"violence\": {\n",
      "          \"filtered\": false,\n",
      "          \"severity\": \"safe\"\n",
      "        }\n",
      "      },\n",
      "      \"finish_reason\": \"stop\",\n",
      "      \"index\": 11,\n",
      "      \"message\": {\n",
      "        \"content\": \"Adding the two equations together gives $3+4+b=4-b+7+a$, which simplifies to $7+b=11+a$. Subtracting $b$ and $a$ from both sides gives $7=11$. Since this is not possible, it means the system of equations does not have a solution.\\n\\nTherefore, we cannot find the value of $3-a$. \\n\\n\\\\boxed{}\",\n",
      "        \"role\": \"assistant\"\n",
      "      }\n",
      "    },\n",
      "    {\n",
      "      \"content_filter_results\": {\n",
      "        \"hate\": {\n",
      "          \"filtered\": false,\n",
      "          \"severity\": \"safe\"\n",
      "        },\n",
      "        \"self_harm\": {\n",
      "          \"filtered\": false,\n",
      "          \"severity\": \"safe\"\n",
      "        },\n",
      "        \"sexual\": {\n",
      "          \"filtered\": false,\n",
      "          \"severity\": \"safe\"\n",
      "        },\n",
      "        \"violence\": {\n",
      "          \"filtered\": false,\n",
      "          \"severity\": \"safe\"\n",
      "        }\n",
      "      },\n",
      "      \"finish_reason\": \"stop\",\n",
      "      \"index\": 12,\n",
      "      \"message\": {\n",
      "        \"content\": \"From the first equation, we have $a=1-b$.\\n\\nSubstitute $a=1-b$ into the second equation:\\n$4+b=7+(1-b)$\\n$4+b=7+1-b$\\n$5=8-b$\\n$b=3$\\n\\nNow, substitute $b=3$ into $a=1-b$:\\n$a=1-3$\\n$a=-2$\\n\\nTherefore, $3-a=3-(-2)=3+2=\\\\boxed{5}$.\",\n",
      "        \"role\": \"assistant\"\n",
      "      }\n",
      "    },\n",
      "    {\n",
      "      \"content_filter_results\": {\n",
      "        \"hate\": {\n",
      "          \"filtered\": false,\n",
      "          \"severity\": \"safe\"\n",
      "        },\n",
      "        \"self_harm\": {\n",
      "          \"filtered\": false,\n",
      "          \"severity\": \"safe\"\n",
      "        },\n",
      "        \"sexual\": {\n",
      "          \"filtered\": false,\n",
      "          \"severity\": \"safe\"\n",
      "        },\n",
      "        \"violence\": {\n",
      "          \"filtered\": false,\n",
      "          \"severity\": \"safe\"\n",
      "        }\n",
      "      },\n",
      "      \"finish_reason\": \"stop\",\n",
      "      \"index\": 13,\n",
      "      \"message\": {\n",
      "        \"content\": \"From the first equation, we have that $a=1-b$. Substituting this into the second equation gives $4+b=7+1-b$, which simplifies to $2b=4$. Dividing both sides by 2 gives $b=2$. Plugging this back into the first equation we have $3+a=4-2$, so $a=-1$.\\n\\nFinally, $3-a=3-(-1)=3+1=\\\\boxed{4}$.\",\n",
      "        \"role\": \"assistant\"\n",
      "      }\n",
      "    },\n",
      "    {\n",
      "      \"content_filter_results\": {\n",
      "        \"hate\": {\n",
      "          \"filtered\": false,\n",
      "          \"severity\": \"safe\"\n",
      "        },\n",
      "        \"self_harm\": {\n",
      "          \"filtered\": false,\n",
      "          \"severity\": \"safe\"\n",
      "        },\n",
      "        \"sexual\": {\n",
      "          \"filtered\": false,\n",
      "          \"severity\": \"safe\"\n",
      "        },\n",
      "        \"violence\": {\n",
      "          \"filtered\": false,\n",
      "          \"severity\": \"safe\"\n",
      "        }\n",
      "      },\n",
      "      \"finish_reason\": \"stop\",\n",
      "      \"index\": 14,\n",
      "      \"message\": {\n",
      "        \"content\": \"From the first equation, we can rewrite as $a+b=1$.\\n\\nFrom the second equation, we can rewrite as $a-b=3$.\\n\\nAdding the two new equations together we have: \\n$a+b+a-b=1+3$\\n$2a=4$\\n$a=2$\\n\\nSubstitute $a=2$ back into $a+b=1$, we have:\\n$2+b=1$\\n$b=-1$\\n\\nTherefore, $3-a=3-2=\\\\boxed{1}$.\",\n",
      "        \"role\": \"assistant\"\n",
      "      }\n",
      "    },\n",
      "    {\n",
      "      \"content_filter_results\": {\n",
      "        \"hate\": {\n",
      "          \"filtered\": false,\n",
      "          \"severity\": \"safe\"\n",
      "        },\n",
      "        \"self_harm\": {\n",
      "          \"filtered\": false,\n",
      "          \"severity\": \"safe\"\n",
      "        },\n",
      "        \"sexual\": {\n",
      "          \"filtered\": false,\n",
      "          \"severity\": \"safe\"\n",
      "        },\n",
      "        \"violence\": {\n",
      "          \"filtered\": false,\n",
      "          \"severity\": \"safe\"\n",
      "        }\n",
      "      },\n",
      "      \"finish_reason\": \"stop\",\n",
      "      \"index\": 15,\n",
      "      \"message\": {\n",
      "        \"content\": \"From the first equation, we get $a = 1-b$.\\nSubstitute $a = 1-b$ into the second equation, we have $4+b = 7+1-b$.\\nSolving this equation for $b$, we get $b = 2$.\\n\\nSubstitute $b=2$ into $a=1-b$, we get $a=-1$.\\n\\nFinally, compute $3-a = 3-(-1) = 4$.\\n\\nTherefore, $\\\\boxed{4}$.\",\n",
      "        \"role\": \"assistant\"\n",
      "      }\n",
      "    },\n",
      "    {\n",
      "      \"content_filter_results\": {\n",
      "        \"hate\": {\n",
      "          \"filtered\": false,\n",
      "          \"severity\": \"safe\"\n",
      "        },\n",
      "        \"self_harm\": {\n",
      "          \"filtered\": false,\n",
      "          \"severity\": \"safe\"\n",
      "        },\n",
      "        \"sexual\": {\n",
      "          \"filtered\": false,\n",
      "          \"severity\": \"safe\"\n",
      "        },\n",
      "        \"violence\": {\n",
      "          \"filtered\": false,\n",
      "          \"severity\": \"safe\"\n",
      "        }\n",
      "      },\n",
      "      \"finish_reason\": \"stop\",\n",
      "      \"index\": 16,\n",
      "      \"message\": {\n",
      "        \"content\": \"To solve for $3-a$, we can first simplify the given equations:  \\\\begin{cases} 3+a=4-b \\\\\\\\ 4+b=7+a \\\\end{cases}\\n\\nFrom the first equation, we can rewrite to solve for $b$ in terms of $a$: $b = 4 - 3 - a = 1 - a$.\\n\\nNow, plug this expression for $b$ into the second equation: $4 + (1 - a) = 7 + a$.\\n\\nSolve for $a$: $5 - a = 7 + a$ \\\\[\\\\Rightarrow 5 = 7 + 2a \\\\Rightarrow 2 = 2a \\\\Rightarrow a = 1\\\\]\\n\\nNow that we've found $a=1$, plug it back in to find $b$: $b = 1 - 1 = 0$.\\n\\nFinally, compute for $3 - a$: $3 - 1 = \\\\boxed{2}$.\",\n",
      "        \"role\": \"assistant\"\n",
      "      }\n",
      "    },\n",
      "    {\n",
      "      \"content_filter_results\": {\n",
      "        \"hate\": {\n",
      "          \"filtered\": false,\n",
      "          \"severity\": \"safe\"\n",
      "        },\n",
      "        \"self_harm\": {\n",
      "          \"filtered\": false,\n",
      "          \"severity\": \"safe\"\n",
      "        },\n",
      "        \"sexual\": {\n",
      "          \"filtered\": false,\n",
      "          \"severity\": \"safe\"\n",
      "        },\n",
      "        \"violence\": {\n",
      "          \"filtered\": false,\n",
      "          \"severity\": \"safe\"\n",
      "        }\n",
      "      },\n",
      "      \"finish_reason\": \"stop\",\n",
      "      \"index\": 17,\n",
      "      \"message\": {\n",
      "        \"content\": \"$3+a=4-b$ can be rearranged to $a+b=1$.\\n\\n$4+b=7+a$ can be rearranged to $a-b=-3$.\\n\\nAdding the two equations, we get $2a= 1-3 \\\\Rightarrow 2a = -2 \\\\Rightarrow a = -1$.\\n\\nSubstitute $a=-1$ into the equation $a+b=1$ to find $b$: $b = 1 -(-1) \\\\Rightarrow b = 2$.\\n\\nFinally, $3-a = 3-(-1) = 3+1=4$\\n\\nTherefore, $\\\\boxed{4}$.\",\n",
      "        \"role\": \"assistant\"\n",
      "      }\n",
      "    },\n",
      "    {\n",
      "      \"content_filter_results\": {\n",
      "        \"hate\": {\n",
      "          \"filtered\": false,\n",
      "          \"severity\": \"safe\"\n",
      "        },\n",
      "        \"self_harm\": {\n",
      "          \"filtered\": false,\n",
      "          \"severity\": \"safe\"\n",
      "        },\n",
      "        \"sexual\": {\n",
      "          \"filtered\": false,\n",
      "          \"severity\": \"safe\"\n",
      "        },\n",
      "        \"violence\": {\n",
      "          \"filtered\": false,\n",
      "          \"severity\": \"safe\"\n",
      "        }\n",
      "      },\n",
      "      \"finish_reason\": \"stop\",\n",
      "      \"index\": 18,\n",
      "      \"message\": {\n",
      "        \"content\": \"First, we can rearrange the given equations to make it easier to solve. \\n\\nFrom the first equation, we have $3+a=4-b$ which can be written as $a+b=1$. \\n\\nSimilarly, from the second equation, we have $4+b=7+a$ which can be rewritten as $a-b=-3$. \\n\\nNow, we have a system of two equations with two variables:\\n\\n$a+b=1$\\n\\n$a-b=-3$\\n\\nSolving this system, we'll add the two equations together to eliminate $b$:\\n\\n$(a+b) + (a-b) = 1 + (-3)$\\n\\n$2a = -2$\\n\\n$a = -1$\\n\\nSubstitute $a=-1$ back into $a+b=1$ to solve for $b$:\\n\\n$-1 + b = 1$\\n\\n$b=2$\\n\\nNow, we need to find $3-a$:\\n\\n$3-(-1) = 3+1 = \\\\boxed{4}$\",\n",
      "        \"role\": \"assistant\"\n",
      "      }\n",
      "    },\n",
      "    {\n",
      "      \"content_filter_results\": {\n",
      "        \"hate\": {\n",
      "          \"filtered\": false,\n",
      "          \"severity\": \"safe\"\n",
      "        },\n",
      "        \"self_harm\": {\n",
      "          \"filtered\": false,\n",
      "          \"severity\": \"safe\"\n",
      "        },\n",
      "        \"sexual\": {\n",
      "          \"filtered\": false,\n",
      "          \"severity\": \"safe\"\n",
      "        },\n",
      "        \"violence\": {\n",
      "          \"filtered\": false,\n",
      "          \"severity\": \"safe\"\n",
      "        }\n",
      "      },\n",
      "      \"finish_reason\": \"stop\",\n",
      "      \"index\": 19,\n",
      "      \"message\": {\n",
      "        \"content\": \"Starting with $3+a=4-b$, let's solve for $b$.\\nAdding $b$ to both sides gives $b+3+a=b+4$.\\nSubtracting $3$ from both sides gives $a=b+1$.\\n\\nNow, substituting $a=b+1$ into the second equation $4+b=7+a$, we get $4+b=7+(b+1)$.\\nSimplifying, we get $4+b=8+b$.\\nSubtracting $b$ from both sides gives $4=8$.\\n\\nThis is impossible, as $4 \\\\neq 8$.\\n\\nSince the systems have no solutions, there is some error in the information you provided. So, $3-a$ cannot be calculated.\",\n",
      "        \"role\": \"assistant\"\n",
      "      }\n",
      "    },\n",
      "    {\n",
      "      \"content_filter_results\": {\n",
      "        \"hate\": {\n",
      "          \"filtered\": false,\n",
      "          \"severity\": \"safe\"\n",
      "        },\n",
      "        \"self_harm\": {\n",
      "          \"filtered\": false,\n",
      "          \"severity\": \"safe\"\n",
      "        },\n",
      "        \"sexual\": {\n",
      "          \"filtered\": false,\n",
      "          \"severity\": \"safe\"\n",
      "        },\n",
      "        \"violence\": {\n",
      "          \"filtered\": false,\n",
      "          \"severity\": \"safe\"\n",
      "        }\n",
      "      },\n",
      "      \"finish_reason\": \"stop\",\n",
      "      \"index\": 20,\n",
      "      \"message\": {\n",
      "        \"content\": \"First, the given equations can be rewritten as $a=1-b$ and $b=3+a$.\\n\\nSubstitute $b=3+a$ into $a=1-b$:\\n$$a=1-(3+a)$$\\n$$a=1-3-a$$\\n$$2a=-2$$\\n$$a=-1$$\\n\\nNow substitute $a=-1$ into $b=3+a$:\\n$$b=3+(-1)$$\\n$$b=2$$\\n\\nFinally, given that $3-a$, substitute $a=-1$:\\n$$3-(-1)$$\\n$$3+1$$\\n$$\\\\boxed{4}$$\",\n",
      "        \"role\": \"assistant\"\n",
      "      }\n",
      "    },\n",
      "    {\n",
      "      \"content_filter_results\": {\n",
      "        \"hate\": {\n",
      "          \"filtered\": false,\n",
      "          \"severity\": \"safe\"\n",
      "        },\n",
      "        \"self_harm\": {\n",
      "          \"filtered\": false,\n",
      "          \"severity\": \"safe\"\n",
      "        },\n",
      "        \"sexual\": {\n",
      "          \"filtered\": false,\n",
      "          \"severity\": \"safe\"\n",
      "        },\n",
      "        \"violence\": {\n",
      "          \"filtered\": false,\n",
      "          \"severity\": \"safe\"\n",
      "        }\n",
      "      },\n",
      "      \"finish_reason\": \"stop\",\n",
      "      \"index\": 21,\n",
      "      \"message\": {\n",
      "        \"content\": \"From the first equation, we can solve for $b$ in terms of $a$ by moving $a$ over as follows:\\n$3+a=4-b$\\n$b = 4-(3+a) = 4-3-a = 1-a$\\n\\nSubstitute this expression for $b$ into the second equation:\\n$4+b=7+a$\\n$4+(1-a)=7+a$\\n$5-a=7+a$\\n$5=7+2a$\\n\\nNow, solve for $a$:\\n$2a = -2$\\n$a = -1$\\n\\nNow that we have $a = -1$, we can find $b$ using $b = 1-a = 1-(-1) = 2$.\\n\\nFinally, calculate $3-a$ using our value for $a$:\\n$3-(-1)=4-2=\\\\boxed{2}$.\",\n",
      "        \"role\": \"assistant\"\n",
      "      }\n",
      "    },\n",
      "    {\n",
      "      \"content_filter_results\": {\n",
      "        \"hate\": {\n",
      "          \"filtered\": false,\n",
      "          \"severity\": \"safe\"\n",
      "        },\n",
      "        \"self_harm\": {\n",
      "          \"filtered\": false,\n",
      "          \"severity\": \"safe\"\n",
      "        },\n",
      "        \"sexual\": {\n",
      "          \"filtered\": false,\n",
      "          \"severity\": \"safe\"\n",
      "        },\n",
      "        \"violence\": {\n",
      "          \"filtered\": false,\n",
      "          \"severity\": \"safe\"\n",
      "        }\n",
      "      },\n",
      "      \"finish_reason\": \"stop\",\n",
      "      \"index\": 22,\n",
      "      \"message\": {\n",
      "        \"content\": \"From the given equations, we can manipulate the equations to isolate $a$ and $b$.\\n\\nFirst, we subtract $a$ from both sides of the first equation to get:\\n\\n$3 = 4-b+a$\\n\\nRearranging this equation gives: \\n\\n$b = 1-a$\\n\\nSimilarly, by subtracting $b$ from both sides of the second equation, we have:\\n\\n$4 = 7+a-b$\\n\\nRearranging this equation gives:\\n\\n$b = 3+a$\\n\\nNow we can substitute $b = 1-a$ into $b = 3+a$:\\n\\n$1-a = 3+a$\\n\\nSolving for $a$ gives: $a = -1$\\n\\nTo find $3-a$, substitute $a = -1$ into $3-a$:\\n\\n$3-(-1) = 3+1 = 4$\\n\\nTherefore, $\\\\boxed{4}$ is the value of $3-a$.\",\n",
      "        \"role\": \"assistant\"\n",
      "      }\n",
      "    },\n",
      "    {\n",
      "      \"content_filter_results\": {\n",
      "        \"hate\": {\n",
      "          \"filtered\": false,\n",
      "          \"severity\": \"safe\"\n",
      "        },\n",
      "        \"self_harm\": {\n",
      "          \"filtered\": false,\n",
      "          \"severity\": \"safe\"\n",
      "        },\n",
      "        \"sexual\": {\n",
      "          \"filtered\": false,\n",
      "          \"severity\": \"safe\"\n",
      "        },\n",
      "        \"violence\": {\n",
      "          \"filtered\": false,\n",
      "          \"severity\": \"safe\"\n",
      "        }\n",
      "      },\n",
      "      \"finish_reason\": \"stop\",\n",
      "      \"index\": 23,\n",
      "      \"message\": {\n",
      "        \"content\": \"From the given equations, we can first isolate $a$ in the first equation:\\n$3 + a = 4 - b$\\n$a = 1 - b$\\n\\nNext, substitute the value of $a$ into the second equation:\\n$4 + b = 7 + a$\\n$4 + b = 7 + (1 - b)$\\n$4 + b = 7 + 1 - b$\\n$4 + b = 8 - b$\\n$2b = 4$\\n$b = 2$\\n\\nNow that we have found the value of $b$, we can substitute it back into the first equation to find $a$:\\n$a = 1 - 2$\\n$a = -1$\\n\\nNow, we can find $3-a$:\\n$3 - (-1) = 3 + 1 = 4$\\n\\nTherefore, $\\\\boxed{4}$ is $3-a$.\",\n",
      "        \"role\": \"assistant\"\n",
      "      }\n",
      "    },\n",
      "    {\n",
      "      \"content_filter_results\": {\n",
      "        \"hate\": {\n",
      "          \"filtered\": false,\n",
      "          \"severity\": \"safe\"\n",
      "        },\n",
      "        \"self_harm\": {\n",
      "          \"filtered\": false,\n",
      "          \"severity\": \"safe\"\n",
      "        },\n",
      "        \"sexual\": {\n",
      "          \"filtered\": false,\n",
      "          \"severity\": \"safe\"\n",
      "        },\n",
      "        \"violence\": {\n",
      "          \"filtered\": false,\n",
      "          \"severity\": \"safe\"\n",
      "        }\n",
      "      },\n",
      "      \"finish_reason\": \"stop\",\n",
      "      \"index\": 24,\n",
      "      \"message\": {\n",
      "        \"content\": \"Starting with the first equation $3+a=4-b$, we can rearrange it to get $a=-b+1$. \\n\\nSubstitute $-b+1$ for $a$ in the second equation $4+b=7+a$ to get $4+b=7+(-b+1)$. Simplifying this equation gives $b-(-b)=7-4-1$, which simplifies to $2b=2$. Therefore, $b=1$.\\n\\nNow substitute $a=-b+1$ into either of the original equations to solve for $a$. Substituting into $3+a=4-b$ gives $3+(-1+1)=4-1$, resulting in $3=3$. Therefore, $a=0$.\\n\\nFinally, we find that $3-a=3-0=\\\\boxed{3}$.\",\n",
      "        \"role\": \"assistant\"\n",
      "      }\n",
      "    },\n",
      "    {\n",
      "      \"content_filter_results\": {\n",
      "        \"hate\": {\n",
      "          \"filtered\": false,\n",
      "          \"severity\": \"safe\"\n",
      "        },\n",
      "        \"self_harm\": {\n",
      "          \"filtered\": false,\n",
      "          \"severity\": \"safe\"\n",
      "        },\n",
      "        \"sexual\": {\n",
      "          \"filtered\": false,\n",
      "          \"severity\": \"safe\"\n",
      "        },\n",
      "        \"violence\": {\n",
      "          \"filtered\": false,\n",
      "          \"severity\": \"safe\"\n",
      "        }\n",
      "      },\n",
      "      \"finish_reason\": \"stop\",\n",
      "      \"index\": 25,\n",
      "      \"message\": {\n",
      "        \"content\": \"Starting with $3+a=4-b$, we can rearrange the equation to get $a = 1-b$. \\n\\nPlugging this into the second equation, $4+b=7+a$, we get $4+b=7+(1-b)$. Simplifying, we have $4+b=8-b$. Solving for $b$, we have $2b=4$, so $b=2$. \\n\\nSubstitute $b=2$ back into $a = 1-b$ to find $a = -1$. \\n\\nFinally, we have $3-a = 3-(-1)= 3+1=\\\\boxed{4}$.\",\n",
      "        \"role\": \"assistant\"\n",
      "      }\n",
      "    },\n",
      "    {\n",
      "      \"content_filter_results\": {\n",
      "        \"hate\": {\n",
      "          \"filtered\": false,\n",
      "          \"severity\": \"safe\"\n",
      "        },\n",
      "        \"self_harm\": {\n",
      "          \"filtered\": false,\n",
      "          \"severity\": \"safe\"\n",
      "        },\n",
      "        \"sexual\": {\n",
      "          \"filtered\": false,\n",
      "          \"severity\": \"safe\"\n",
      "        },\n",
      "        \"violence\": {\n",
      "          \"filtered\": false,\n",
      "          \"severity\": \"safe\"\n",
      "        }\n",
      "      },\n",
      "      \"finish_reason\": \"stop\",\n",
      "      \"index\": 26,\n",
      "      \"message\": {\n",
      "        \"content\": \"To find the value of $3-a$, we will first solve the two given equations for $a$ and $b$.\\n\\nFrom $3+a=4-b$, we can isolate $b$ as follows:\\n$a = 4-b-3$\\n$a = 1-b$\\n$b = 1-a$   (Equation 1)\\n\\nSimilarly, from $4+b = 7+a$, we can isolate $b$ as follows:\\n$b = 7+a-4$\\n$b = 3+a$   (Equation 2)\\n\\nNow, equating the $b$ values from Equation 1 and Equation 2:\\n$1-a = 3+a$\\n$1-3 = a+a$\\n$a = -1$\\n\\nSubstitute $a = -1$ into $b = 3+a$ from Equation 2:\\n$b = 3+(-1)$\\n$b = 2$\\n\\nNow that we have found the values of $a$ and $b$ to be $-1$ and $2$ respectively, we can find $3-a$:\\n$3-a = 3-(-1) = 3+1 = 4$\\n\\nTherefore, $\\\\boxed{4}$ is the value of $3-a$.\",\n",
      "        \"role\": \"assistant\"\n",
      "      }\n",
      "    },\n",
      "    {\n",
      "      \"content_filter_results\": {\n",
      "        \"hate\": {\n",
      "          \"filtered\": false,\n",
      "          \"severity\": \"safe\"\n",
      "        },\n",
      "        \"self_harm\": {\n",
      "          \"filtered\": false,\n",
      "          \"severity\": \"safe\"\n",
      "        },\n",
      "        \"sexual\": {\n",
      "          \"filtered\": false,\n",
      "          \"severity\": \"safe\"\n",
      "        },\n",
      "        \"violence\": {\n",
      "          \"filtered\": false,\n",
      "          \"severity\": \"safe\"\n",
      "        }\n",
      "      },\n",
      "      \"finish_reason\": \"stop\",\n",
      "      \"index\": 27,\n",
      "      \"message\": {\n",
      "        \"content\": \"First, we will solve the given equations for $a$ and $b$.\\nFrom the first equation, $3 + a = 4 - b$, we get:\\n$a = 1 - b$.\\n\\nPlugging this back into the second equation $4 + b = 7 + a$, we get:\\n$4 + b = 7 + (1 - b)$.\\n$4 + b = 7 + 1 - b$.\\n$5 + b = 8$.\\n$b = 3$.\\n\\nNow, by plugging the value of $b$ back into $a = 1 - b$, we get:\\n$a = 1 - 3$.\\n$a = -2$.\\n\\nTherefore, $3 - a = 3 - (-2) = 3 + 2 = \\\\boxed{5}$.\",\n",
      "        \"role\": \"assistant\"\n",
      "      }\n",
      "    },\n",
      "    {\n",
      "      \"content_filter_results\": {\n",
      "        \"hate\": {\n",
      "          \"filtered\": false,\n",
      "          \"severity\": \"safe\"\n",
      "        },\n",
      "        \"self_harm\": {\n",
      "          \"filtered\": false,\n",
      "          \"severity\": \"safe\"\n",
      "        },\n",
      "        \"sexual\": {\n",
      "          \"filtered\": false,\n",
      "          \"severity\": \"safe\"\n",
      "        },\n",
      "        \"violence\": {\n",
      "          \"filtered\": false,\n",
      "          \"severity\": \"safe\"\n",
      "        }\n",
      "      },\n",
      "      \"finish_reason\": \"stop\",\n",
      "      \"index\": 28,\n",
      "      \"message\": {\n",
      "        \"content\": \"We have the two equations:\\n\\n1) $3+a=4-b$\\n2) $4+b=7+a$\\n\\nRearranging the equations, we get:\\n\\n1) $a+b=1$\\n2) $a-b=3$\\n\\nAdding the two equations together gives us:\\n$(a+b) + (a-b) = 1 + 3$\\n$2a = 4$\\n$a = 2$\\n\\nSubstitute $a=2$ back into equation 1) to solve for $b$:\\n$2 + b = 1$\\n$b = -1$\\n\\nNow, we can calculate $3-a$:\\n$3-a = 3-2 = \\\\boxed{1}$\",\n",
      "        \"role\": \"assistant\"\n",
      "      }\n",
      "    },\n",
      "    {\n",
      "      \"content_filter_results\": {\n",
      "        \"hate\": {\n",
      "          \"filtered\": false,\n",
      "          \"severity\": \"safe\"\n",
      "        },\n",
      "        \"self_harm\": {\n",
      "          \"filtered\": false,\n",
      "          \"severity\": \"safe\"\n",
      "        },\n",
      "        \"sexual\": {\n",
      "          \"filtered\": false,\n",
      "          \"severity\": \"safe\"\n",
      "        },\n",
      "        \"violence\": {\n",
      "          \"filtered\": false,\n",
      "          \"severity\": \"safe\"\n",
      "        }\n",
      "      },\n",
      "      \"finish_reason\": \"stop\",\n",
      "      \"index\": 29,\n",
      "      \"message\": {\n",
      "        \"content\": \"Starting with the given equations:\\n$$3+a=4-b$$\\n$$4+b=7+a$$\\n\\nRearranging the first equation to solve for $b$, we get:\\n$$b = 4-3-a = 1-a$$\\n\\nSubstitute this value of $b$ into the second equation and solve for $a$:\\n$$4+1-a=7+a$$\\n$$5-a=7+a$$\\n$$5=2a+7$$\\n$$2a=-2$$\\n$$a=-1$$\\n\\nNow, substitute $a=-1$ back into the first equation to find $b$:\\n$$3-1=4-b$$\\n$$2=4-b$$\\n$$b=2$$\\n\\nFinally, calculate $3-a$:\\n$$3-(-1) = 3+1 = 4$$\\n\\n$$\\\\boxed{4}$$\",\n",
      "        \"role\": \"assistant\"\n",
      "      }\n",
      "    },\n",
      "    {\n",
      "      \"content_filter_results\": {\n",
      "        \"hate\": {\n",
      "          \"filtered\": false,\n",
      "          \"severity\": \"safe\"\n",
      "        },\n",
      "        \"self_harm\": {\n",
      "          \"filtered\": false,\n",
      "          \"severity\": \"safe\"\n",
      "        },\n",
      "        \"sexual\": {\n",
      "          \"filtered\": false,\n",
      "          \"severity\": \"safe\"\n",
      "        },\n",
      "        \"violence\": {\n",
      "          \"filtered\": false,\n",
      "          \"severity\": \"safe\"\n",
      "        }\n",
      "      },\n",
      "      \"finish_reason\": \"stop\",\n",
      "      \"index\": 30,\n",
      "      \"message\": {\n",
      "        \"content\": \"Given:\\n1. $3+a=4-b$\\n2. $4+b=7+a$\\n\\nRearranging equation 1, we have:\\n$a=b+1$\\n\\nSubstitute $a=b+1$ into equation 2:\\n$4+b=7+(b+1)$\\n$4+b=7+b+1$\\n$4+b=8+b$\\n\\nSubtracting $b$ from both sides:\\n$4=8$\\n\\nThis is a contradiction; therefore, the system of equations provided is inconsistent and has no solution. \\n\\nHence, $3-a$ does not have a unique numerical value.\\n\\n\\\\boxed{There is no solution for this system of equations.}\",\n",
      "        \"role\": \"assistant\"\n",
      "      }\n",
      "    },\n",
      "    {\n",
      "      \"content_filter_results\": {\n",
      "        \"hate\": {\n",
      "          \"filtered\": false,\n",
      "          \"severity\": \"safe\"\n",
      "        },\n",
      "        \"self_harm\": {\n",
      "          \"filtered\": false,\n",
      "          \"severity\": \"safe\"\n",
      "        },\n",
      "        \"sexual\": {\n",
      "          \"filtered\": false,\n",
      "          \"severity\": \"safe\"\n",
      "        },\n",
      "        \"violence\": {\n",
      "          \"filtered\": false,\n",
      "          \"severity\": \"safe\"\n",
      "        }\n",
      "      },\n",
      "      \"finish_reason\": \"stop\",\n",
      "      \"index\": 31,\n",
      "      \"message\": {\n",
      "        \"content\": \"First, let's simplify the given equations:\\n1) $3+a=4-b \\\\implies a+b=1$\\n2) $4+b=7+a \\\\implies a-b=3$\\n\\nNow, we have a system of equations:\\n$a+b=1$\\n$a-b=3$\\n\\nAdding the two equations, we get:\\n$2a=4 \\\\implies a=2$\\n\\nSubstitute $a=2$ into $a+b=1$, we get:\\n$2+b=1 \\\\implies b=-1$\\n\\nNow, we want to find $3-a$:\\n$3-a=3-2=\\\\boxed{1}$\",\n",
      "        \"role\": \"assistant\"\n",
      "      }\n",
      "    },\n",
      "    {\n",
      "      \"content_filter_results\": {\n",
      "        \"hate\": {\n",
      "          \"filtered\": false,\n",
      "          \"severity\": \"safe\"\n",
      "        },\n",
      "        \"self_harm\": {\n",
      "          \"filtered\": false,\n",
      "          \"severity\": \"safe\"\n",
      "        },\n",
      "        \"sexual\": {\n",
      "          \"filtered\": false,\n",
      "          \"severity\": \"safe\"\n",
      "        },\n",
      "        \"violence\": {\n",
      "          \"filtered\": false,\n",
      "          \"severity\": \"safe\"\n",
      "        }\n",
      "      },\n",
      "      \"finish_reason\": \"stop\",\n",
      "      \"index\": 32,\n",
      "      \"message\": {\n",
      "        \"content\": \"We solve the system of equations:\\n\\nFrom $3+a=4-b$, we have $a=-b+1$.\\n\\nSubstitute $a$ into the second equation $4+b=7+a$:\\n\\n$4+b=7+(-b+1)$\\n\\n$4+b=8-b$\\n\\n$2b=4$\\n\\n$b=2$\\n\\nPlug $b=2$ back into $a=-b+1$ to find $a$:\\n\\n$a=-2+1=-1$\\n\\nFinally, $3-a=3-(-1)=3+1=\\\\boxed{4}$.\",\n",
      "        \"role\": \"assistant\"\n",
      "      }\n",
      "    },\n",
      "    {\n",
      "      \"content_filter_results\": {\n",
      "        \"hate\": {\n",
      "          \"filtered\": false,\n",
      "          \"severity\": \"safe\"\n",
      "        },\n",
      "        \"self_harm\": {\n",
      "          \"filtered\": false,\n",
      "          \"severity\": \"safe\"\n",
      "        },\n",
      "        \"sexual\": {\n",
      "          \"filtered\": false,\n",
      "          \"severity\": \"safe\"\n",
      "        },\n",
      "        \"violence\": {\n",
      "          \"filtered\": false,\n",
      "          \"severity\": \"safe\"\n",
      "        }\n",
      "      },\n",
      "      \"finish_reason\": \"stop\",\n",
      "      \"index\": 33,\n",
      "      \"message\": {\n",
      "        \"content\": \"First, let's solve the system of equations: \\n$3 + a = 4 - b$  \\n$4 + b = 7 + a$\\n\\nRearranging the first equation gives:  \\n$3 - 4 = -b -a$  \\n$b + a = -1...*(i)$\\n\\nAlso,\\n\\nRearranging the second equation gives:    \\n$4 -7 = a - b$  \\n$a - b = -3...*(ii)$\\n\\nNow, add equations $(i)$ and $(ii)$:\\n\\n$b+a + a-b = -1 + (-3)$  \\n$2a = -4$  \\n$a = -2$\\n\\nSubstitute $a = -2$ back into equation $(i)$ to find $b$:\\n\\n$b + (-2) = -1$  \\n$b = 1$\\n\\nNow, we are asked to find $3-a$. To solve for this value:\\n\\n$3 - (-2) = 3 + 2 = 5$\\n\\nTherefore, $\\\\boxed{5}$ is the solution for $3-a$.\",\n",
      "        \"role\": \"assistant\"\n",
      "      }\n",
      "    },\n",
      "    {\n",
      "      \"content_filter_results\": {\n",
      "        \"hate\": {\n",
      "          \"filtered\": false,\n",
      "          \"severity\": \"safe\"\n",
      "        },\n",
      "        \"self_harm\": {\n",
      "          \"filtered\": false,\n",
      "          \"severity\": \"safe\"\n",
      "        },\n",
      "        \"sexual\": {\n",
      "          \"filtered\": false,\n",
      "          \"severity\": \"safe\"\n",
      "        },\n",
      "        \"violence\": {\n",
      "          \"filtered\": false,\n",
      "          \"severity\": \"safe\"\n",
      "        }\n",
      "      },\n",
      "      \"finish_reason\": \"stop\",\n",
      "      \"index\": 34,\n",
      "      \"message\": {\n",
      "        \"content\": \"First, let's rewrite the system of equations in terms of $a$ and $b$:\\n\\nFrom $3+a=4-b$, we get $a=-4+b$\\n\\nSubstitute $a$ with $-4+b$ in the second equation $4+b=7+a$, we get $4+b=7+(-4+b)$, which simplifies to $4+b=3+b$ or $1=0$\\n\\nSince $1=0$, this system of equations has no solution. Thus, any expression involving $a$ and $b$ does not have a definite value. \\n\\nTherefore, $\\\\boxed{}$\",\n",
      "        \"role\": \"assistant\"\n",
      "      }\n",
      "    },\n",
      "    {\n",
      "      \"content_filter_results\": {\n",
      "        \"hate\": {\n",
      "          \"filtered\": false,\n",
      "          \"severity\": \"safe\"\n",
      "        },\n",
      "        \"self_harm\": {\n",
      "          \"filtered\": false,\n",
      "          \"severity\": \"safe\"\n",
      "        },\n",
      "        \"sexual\": {\n",
      "          \"filtered\": false,\n",
      "          \"severity\": \"safe\"\n",
      "        },\n",
      "        \"violence\": {\n",
      "          \"filtered\": false,\n",
      "          \"severity\": \"safe\"\n",
      "        }\n",
      "      },\n",
      "      \"finish_reason\": \"stop\",\n",
      "      \"index\": 35,\n",
      "      \"message\": {\n",
      "        \"content\": \"Adding the equations $3+a=4-b$ and $4+b=7+a$, we get:\\n\\n$(3+a)+(4+b) = (4-b) + (7+a) \\\\\\\\\\n3 + a + 4 + b = 4 - b + 7 + a \\\\\\\\\\n7 + a + b = 11 + a$\\n\\nSubtracting $a$ from both sides gives: \\n\\n$7 + b = 11$\\n\\nSubtracting 7 from both sides gives:\\n\\n$b = 4$\\n\\nPlugging this result back into the first equation, we get:\\n\\n$3+a=4-4 \\\\\\\\\\n3+a=0 \\\\\\\\\\na = -3$\\n\\nTherefore, $3-a = 3-(-3) = 3+3 = 6$.\\n\\nSo, $\\\\boxed{6}$ is the final answer.\",\n",
      "        \"role\": \"assistant\"\n",
      "      }\n",
      "    },\n",
      "    {\n",
      "      \"content_filter_results\": {\n",
      "        \"hate\": {\n",
      "          \"filtered\": false,\n",
      "          \"severity\": \"safe\"\n",
      "        },\n",
      "        \"self_harm\": {\n",
      "          \"filtered\": false,\n",
      "          \"severity\": \"safe\"\n",
      "        },\n",
      "        \"sexual\": {\n",
      "          \"filtered\": false,\n",
      "          \"severity\": \"safe\"\n",
      "        },\n",
      "        \"violence\": {\n",
      "          \"filtered\": false,\n",
      "          \"severity\": \"safe\"\n",
      "        }\n",
      "      },\n",
      "      \"finish_reason\": \"stop\",\n",
      "      \"index\": 36,\n",
      "      \"message\": {\n",
      "        \"content\": \"Given equations:\\n1. $3+a=4-b$\\n2. $4+b=7+a$\\n\\nRearrange equation 1 to solve for $b$:\\n$3+a=4-b\\\\\\\\\\nb=4-(3+a)\\\\\\\\\\nb=4-3-a\\\\\\\\\\nb=1-a$\\n\\nSubstitute $b=1-a$ into equation 2:\\n$4+1-a=7+a\\\\\\\\\\n5-a=7+a\\\\\\\\\\n-a-a=7-5\\\\\\\\\\n-2a=2\\\\\\\\\\na=-1$\\n\\nNow that we have the value of $a=-1$, we can calculate for $b$ using the earlier derived expression for $b=1-a$:\\n$b=1-(-1)\\\\\\\\\\nb=1+1\\\\\\\\\\nb=2$\\n\\nFinally, we can calculate $3-a$ using the value of $a=-1$:\\n$3-(-1)\\\\\\\\\\n3+1\\\\\\\\\\n\\\\boxed{4}$\",\n",
      "        \"role\": \"assistant\"\n",
      "      }\n",
      "    },\n",
      "    {\n",
      "      \"content_filter_results\": {\n",
      "        \"hate\": {\n",
      "          \"filtered\": false,\n",
      "          \"severity\": \"safe\"\n",
      "        },\n",
      "        \"self_harm\": {\n",
      "          \"filtered\": false,\n",
      "          \"severity\": \"safe\"\n",
      "        },\n",
      "        \"sexual\": {\n",
      "          \"filtered\": false,\n",
      "          \"severity\": \"safe\"\n",
      "        },\n",
      "        \"violence\": {\n",
      "          \"filtered\": false,\n",
      "          \"severity\": \"safe\"\n",
      "        }\n",
      "      },\n",
      "      \"finish_reason\": \"stop\",\n",
      "      \"index\": 37,\n",
      "      \"message\": {\n",
      "        \"content\": \"Starting with the first equation, we can rearrange it to isolate $a$:\\n$a=1-b$\\n\\nSubstitute this into the second equation:\\n$4+b=7+1-b$\\n\\nCombining like terms:\\n$2b=4$\\n\\nSolving for $b$:\\n$b=2$\\n\\nPlug this back into the first equation to solve for $a$:\\n$a=1-2=-1$\\n\\nFinally finding $3-a$:\\n$3-(-1)=3+1=\\\\boxed{4}$\",\n",
      "        \"role\": \"assistant\"\n",
      "      }\n",
      "    },\n",
      "    {\n",
      "      \"content_filter_results\": {\n",
      "        \"hate\": {\n",
      "          \"filtered\": false,\n",
      "          \"severity\": \"safe\"\n",
      "        },\n",
      "        \"self_harm\": {\n",
      "          \"filtered\": false,\n",
      "          \"severity\": \"safe\"\n",
      "        },\n",
      "        \"sexual\": {\n",
      "          \"filtered\": false,\n",
      "          \"severity\": \"safe\"\n",
      "        },\n",
      "        \"violence\": {\n",
      "          \"filtered\": false,\n",
      "          \"severity\": \"safe\"\n",
      "        }\n",
      "      },\n",
      "      \"finish_reason\": \"stop\",\n",
      "      \"index\": 38,\n",
      "      \"message\": {\n",
      "        \"content\": \"Adding the two equations gives:\\n\\n$(3+a)+(4+b)=4-b+7+a \\\\\\\\\\n7+a+b=11+a \\\\\\\\\\nb=4$\\n\\nSubstitute $b=4$ into the first equation:\\n\\n$3+a=4-4 \\\\\\\\\\n3+a=0 \\\\\\\\\\na=-3$\\n\\nTherefore, $3-a=3-(-3)=3+3=\\\\boxed{6}$.\",\n",
      "        \"role\": \"assistant\"\n",
      "      }\n",
      "    },\n",
      "    {\n",
      "      \"content_filter_results\": {\n",
      "        \"hate\": {\n",
      "          \"filtered\": false,\n",
      "          \"severity\": \"safe\"\n",
      "        },\n",
      "        \"self_harm\": {\n",
      "          \"filtered\": false,\n",
      "          \"severity\": \"safe\"\n",
      "        },\n",
      "        \"sexual\": {\n",
      "          \"filtered\": false,\n",
      "          \"severity\": \"safe\"\n",
      "        },\n",
      "        \"violence\": {\n",
      "          \"filtered\": false,\n",
      "          \"severity\": \"safe\"\n",
      "        }\n",
      "      },\n",
      "      \"finish_reason\": \"stop\",\n",
      "      \"index\": 39,\n",
      "      \"message\": {\n",
      "        \"content\": \"First, let's solve for $a$ and $b$ by writing the given equations as a system of linear equations:\\n\\n1. $3+a=4-b$\\n$3+a = 4 - b$\\n$a + b = 1$ --> Equation 1\\n\\n2. $4+b=7+a$\\n$4 + b = 7 + a$\\n$b - a = 3$ --> Equation 2\\n\\nAdding Equations 1 and 2 gives:\\n$(a + b) + (b - a) = 1 + 3$\\n$2b = 4$\\n$b = 2$\\n\\nSubstitute $b = 2$ back into Equation 1 gives:\\n$a + 2 = 1$\\n$a = -1$\\n\\nNow, we need to find $3 - a$:\\n$3 - a = 3 - (-1) = 4$\\n\\nSo, $\\\\boxed{4}$ is the value of $3 - a$.\",\n",
      "        \"role\": \"assistant\"\n",
      "      }\n",
      "    },\n",
      "    {\n",
      "      \"content_filter_results\": {\n",
      "        \"hate\": {\n",
      "          \"filtered\": false,\n",
      "          \"severity\": \"safe\"\n",
      "        },\n",
      "        \"self_harm\": {\n",
      "          \"filtered\": false,\n",
      "          \"severity\": \"safe\"\n",
      "        },\n",
      "        \"sexual\": {\n",
      "          \"filtered\": false,\n",
      "          \"severity\": \"safe\"\n",
      "        },\n",
      "        \"violence\": {\n",
      "          \"filtered\": false,\n",
      "          \"severity\": \"safe\"\n",
      "        }\n",
      "      },\n",
      "      \"finish_reason\": \"stop\",\n",
      "      \"index\": 40,\n",
      "      \"message\": {\n",
      "        \"content\": \"Given equations are:\\n1) $3+a=4-b$,\\n2) $4+b=7+a$.\\n\\nRearranging equations:\\n1) $a+b=1$,\\n2) $a-b=3$.\\n\\nAdding both equations we get:\\n$(a+b) + (a-b) = 1+3$,\\n$2a=4$, then $a=2$.\\n\\nNow substitue the value of $a$ to equation $a+b=1$ we get:\\n$2+b=1$, then $b=-1$.\\n\\nNow, to find $3-a$:\\n$3-a=3-2=1$.\\n\\nFinal answer is $\\\\boxed{1}$.\",\n",
      "        \"role\": \"assistant\"\n",
      "      }\n",
      "    },\n",
      "    {\n",
      "      \"content_filter_results\": {\n",
      "        \"hate\": {\n",
      "          \"filtered\": false,\n",
      "          \"severity\": \"safe\"\n",
      "        },\n",
      "        \"self_harm\": {\n",
      "          \"filtered\": false,\n",
      "          \"severity\": \"safe\"\n",
      "        },\n",
      "        \"sexual\": {\n",
      "          \"filtered\": false,\n",
      "          \"severity\": \"safe\"\n",
      "        },\n",
      "        \"violence\": {\n",
      "          \"filtered\": false,\n",
      "          \"severity\": \"safe\"\n",
      "        }\n",
      "      },\n",
      "      \"finish_reason\": \"stop\",\n",
      "      \"index\": 41,\n",
      "      \"message\": {\n",
      "        \"content\": \"First, we can simplify the two equations:\\n\\\\[3+a=4-b \\\\ \\\\Rightarrow a-b=1\\\\]\\n\\\\[4+b=7+a \\\\ \\\\Rightarrow b-a=3\\\\]\\n\\nAdding these two equations together we get:\\n\\\\[a-b+b-a=1+3\\\\]\\n\\\\[0=4\\\\]\\n\\nThis means that the equations given do not have a solution and they are inconsistent. Therefore, we cannot determine the value of $3-a$. So, the answer is:\\n\\n\\\\[\\\\boxed{\\\\text{No solution}}\\\\]\",\n",
      "        \"role\": \"assistant\"\n",
      "      }\n",
      "    },\n",
      "    {\n",
      "      \"content_filter_results\": {\n",
      "        \"hate\": {\n",
      "          \"filtered\": false,\n",
      "          \"severity\": \"safe\"\n",
      "        },\n",
      "        \"self_harm\": {\n",
      "          \"filtered\": false,\n",
      "          \"severity\": \"safe\"\n",
      "        },\n",
      "        \"sexual\": {\n",
      "          \"filtered\": false,\n",
      "          \"severity\": \"safe\"\n",
      "        },\n",
      "        \"violence\": {\n",
      "          \"filtered\": false,\n",
      "          \"severity\": \"safe\"\n",
      "        }\n",
      "      },\n",
      "      \"finish_reason\": \"stop\",\n",
      "      \"index\": 42,\n",
      "      \"message\": {\n",
      "        \"content\": \"First, let's solve the equations simultaneously.\\n\\nFrom $3+a=4-b$, we get $a=1-b$.\\n\\nSubstitute $a=1-b$ into $4+b=7+a$, we get $4+b=7+1-b$.\\n\\nSolving this, we get $b=2$.\\n\\nSubstitute $b=2$ into $a=1-b$, we get $a=-1$.\\n\\nNow, solve for $3-a$.\\n\\n$3-a=3-(-1)=3+1=4$.\\n\\nTherefore, $\\\\boxed{4}$.\",\n",
      "        \"role\": \"assistant\"\n",
      "      }\n",
      "    },\n",
      "    {\n",
      "      \"content_filter_results\": {\n",
      "        \"hate\": {\n",
      "          \"filtered\": false,\n",
      "          \"severity\": \"safe\"\n",
      "        },\n",
      "        \"self_harm\": {\n",
      "          \"filtered\": false,\n",
      "          \"severity\": \"safe\"\n",
      "        },\n",
      "        \"sexual\": {\n",
      "          \"filtered\": false,\n",
      "          \"severity\": \"safe\"\n",
      "        },\n",
      "        \"violence\": {\n",
      "          \"filtered\": false,\n",
      "          \"severity\": \"safe\"\n",
      "        }\n",
      "      },\n",
      "      \"finish_reason\": \"stop\",\n",
      "      \"index\": 43,\n",
      "      \"message\": {\n",
      "        \"content\": \"Starting with $3+a=4-b$, we can rearrange to get $a=b+1$.\\n\\nNext, substituting $a=b+1$ into $4+b=7+a$, we get $4+b=7+(b+1)$. This simplifies to $4+b=8+b$ which means $b=4$.\\n\\nFinally, substituting $b=4$ into $a=b+1$, we get $a=4+1=5$.\\n\\nTherefore, $3-a=3-5=-2$. \\n\\nSo, $\\\\boxed{-2}$ is the final answer.\",\n",
      "        \"role\": \"assistant\"\n",
      "      }\n",
      "    },\n",
      "    {\n",
      "      \"content_filter_results\": {\n",
      "        \"hate\": {\n",
      "          \"filtered\": false,\n",
      "          \"severity\": \"safe\"\n",
      "        },\n",
      "        \"self_harm\": {\n",
      "          \"filtered\": false,\n",
      "          \"severity\": \"safe\"\n",
      "        },\n",
      "        \"sexual\": {\n",
      "          \"filtered\": false,\n",
      "          \"severity\": \"safe\"\n",
      "        },\n",
      "        \"violence\": {\n",
      "          \"filtered\": false,\n",
      "          \"severity\": \"safe\"\n",
      "        }\n",
      "      },\n",
      "      \"finish_reason\": \"stop\",\n",
      "      \"index\": 44,\n",
      "      \"message\": {\n",
      "        \"content\": \"To find $3-a$, we need to find the value of $a$ first. \\n\\nFrom the first equation provided, $3 + a = 4 - b$, we can rearrange it to get $a = 4 - b - 3 \\\\Rightarrow a = 1 - b$. \\n\\nNow we can substitute this expression for $a$ into the second equation provided, $4 + b = 7 + a$. \\n\\nSubstitute $a = 1 - b$ into $4 + b = 7 + a$:\\n\\n$4 + b = 7 + 1 - b$\\n\\nCombine like terms:\\n\\n$b + b = 8$\\n\\n$2b  = 8$\\n\\n$\\u200bb = 4$\\n\\nNow that we have found the value of $b$, we can find the value of $a$ using $a = 1 - b$:\\n\\n$a = 1 - 4 $\\n\\n$a  = -3$\\n\\nFinally, we can find $3 - a$ as requested:\\n\\n$3 - a = 3 - (-3) = 3 + 3 = 6$\\n\\nThus, $\\\\boxed{6}$.\",\n",
      "        \"role\": \"assistant\"\n",
      "      }\n",
      "    },\n",
      "    {\n",
      "      \"content_filter_results\": {\n",
      "        \"hate\": {\n",
      "          \"filtered\": false,\n",
      "          \"severity\": \"safe\"\n",
      "        },\n",
      "        \"self_harm\": {\n",
      "          \"filtered\": false,\n",
      "          \"severity\": \"safe\"\n",
      "        },\n",
      "        \"sexual\": {\n",
      "          \"filtered\": false,\n",
      "          \"severity\": \"safe\"\n",
      "        },\n",
      "        \"violence\": {\n",
      "          \"filtered\": false,\n",
      "          \"severity\": \"safe\"\n",
      "        }\n",
      "      },\n",
      "      \"finish_reason\": \"stop\",\n",
      "      \"index\": 45,\n",
      "      \"message\": {\n",
      "        \"content\": \"Given equations:\\n\\n(1) $3 + a = 4 - b$\\n\\n(2) $4 + b = 7 + a$\\n\\nRearrange equation (1) to express a in terms of b:\\n\\n$a = 4 - b - 3 = 1 - b$\\n\\nSubstitute this into equation (2):\\n\\n$4 + b = 7 + (1 - b)$\\n\\nSolve for b:\\n\\n$4 + b = 7 + 1 - b$\\n\\n$5 + b = 7$\\n\\n$b = 2$\\n\\nNow that we have found b, substitute it back into the equation to find a:\\n\\n$a = 1 - 2 = -1$\\n\\nFinally, calculate $3 - a$:\\n\\n$3 - (-1) = 3 + 1 = 4$\\n\\nSo, $\\\\boxed{4}$ is the final answer.\",\n",
      "        \"role\": \"assistant\"\n",
      "      }\n",
      "    },\n",
      "    {\n",
      "      \"content_filter_results\": {\n",
      "        \"hate\": {\n",
      "          \"filtered\": false,\n",
      "          \"severity\": \"safe\"\n",
      "        },\n",
      "        \"self_harm\": {\n",
      "          \"filtered\": false,\n",
      "          \"severity\": \"safe\"\n",
      "        },\n",
      "        \"sexual\": {\n",
      "          \"filtered\": false,\n",
      "          \"severity\": \"safe\"\n",
      "        },\n",
      "        \"violence\": {\n",
      "          \"filtered\": false,\n",
      "          \"severity\": \"safe\"\n",
      "        }\n",
      "      },\n",
      "      \"finish_reason\": \"stop\",\n",
      "      \"index\": 46,\n",
      "      \"message\": {\n",
      "        \"content\": \"Given that $3+a=4-b$ and $4+b=7+a$, we can solve this system of equations by combining them.\\n\\nFrom the first equation, we get $a=4-b-3=1-b$.\\n\\nSubstitute $a=1-b$ into the second equation, we have $4+b=7+(1-b)$\\nExpand the right side, we get $4+b=8-b$\\n\\nAdding $b$ to both sides gives $5=8$\\n\\nThis statement is clearly false, so there is no solution to this system of equations.\\n\\nTherefore, $3-a$ does not have a unique value. \\n\\n$\\\\boxed{\\\\text{No solution}}$\",\n",
      "        \"role\": \"assistant\"\n",
      "      }\n",
      "    },\n",
      "    {\n",
      "      \"content_filter_results\": {\n",
      "        \"hate\": {\n",
      "          \"filtered\": false,\n",
      "          \"severity\": \"safe\"\n",
      "        },\n",
      "        \"self_harm\": {\n",
      "          \"filtered\": false,\n",
      "          \"severity\": \"safe\"\n",
      "        },\n",
      "        \"sexual\": {\n",
      "          \"filtered\": false,\n",
      "          \"severity\": \"safe\"\n",
      "        },\n",
      "        \"violence\": {\n",
      "          \"filtered\": false,\n",
      "          \"severity\": \"safe\"\n",
      "        }\n",
      "      },\n",
      "      \"finish_reason\": \"stop\",\n",
      "      \"index\": 47,\n",
      "      \"message\": {\n",
      "        \"content\": \"From the first equation, we have:\\n\\n$$3+a=4-b$$\\n$$a-b=1 \\\\quad \\\\text{(1)}$$\\n\\nFrom the second equation, we have:\\n\\n$$4+b=7+a$$\\n$$b-a=3 \\\\quad \\\\text{(2)}$$\\n\\nAdding equations (1) and (2), we get:\\n\\n$$2b = 4$$\\n$$b = 2$$\\n\\nPlugging the value of $b$ back into equation (1):\\n\\n$$a-2=1$$\\n$$a = 3$$\\n\\nTherefore, $3-a = 3-3 = 0$. \\n\\nSo, $\\\\boxed{0}$ is the answer.\",\n",
      "        \"role\": \"assistant\"\n",
      "      }\n",
      "    },\n",
      "    {\n",
      "      \"content_filter_results\": {\n",
      "        \"hate\": {\n",
      "          \"filtered\": false,\n",
      "          \"severity\": \"safe\"\n",
      "        },\n",
      "        \"self_harm\": {\n",
      "          \"filtered\": false,\n",
      "          \"severity\": \"safe\"\n",
      "        },\n",
      "        \"sexual\": {\n",
      "          \"filtered\": false,\n",
      "          \"severity\": \"safe\"\n",
      "        },\n",
      "        \"violence\": {\n",
      "          \"filtered\": false,\n",
      "          \"severity\": \"safe\"\n",
      "        }\n",
      "      },\n",
      "      \"finish_reason\": \"stop\",\n",
      "      \"index\": 48,\n",
      "      \"message\": {\n",
      "        \"content\": \"Let's solve the given system of equations one step at a time.\\n\\n1. From $3 + a = 4 - b$, we can isolate $b$:\\n$3 + a = 4 - b$\\n$b = 4 - 3 - a$\\n$b = 1 - a$\\n\\n2. Substitute $1 - a$ for $b$ in the second equation $4 + b = 7 + a$:\\n$4 + (1 - a) = 7 + a$\\n$4 + 1 - a = 7 + a$\\n$5 - a = 7 + a$\\n$a + a = 7 - 5$\\n$2a = 2$\\n$a = 1$\\n\\n3. Substitute $a = 1$ back into $b = 1 - a$:\\n$b = 1 - 1$\\n$b = 0$\\n\\n4. Find $3 - a$ using $a = 1$:\\n$3 - a = 3 - 1 = 2$\\n\\nTherefore, the final answer is $\\\\boxed{2}$.\",\n",
      "        \"role\": \"assistant\"\n",
      "      }\n",
      "    },\n",
      "    {\n",
      "      \"content_filter_results\": {\n",
      "        \"hate\": {\n",
      "          \"filtered\": false,\n",
      "          \"severity\": \"safe\"\n",
      "        },\n",
      "        \"self_harm\": {\n",
      "          \"filtered\": false,\n",
      "          \"severity\": \"safe\"\n",
      "        },\n",
      "        \"sexual\": {\n",
      "          \"filtered\": false,\n",
      "          \"severity\": \"safe\"\n",
      "        },\n",
      "        \"violence\": {\n",
      "          \"filtered\": false,\n",
      "          \"severity\": \"safe\"\n",
      "        }\n",
      "      },\n",
      "      \"finish_reason\": \"stop\",\n",
      "      \"index\": 49,\n",
      "      \"message\": {\n",
      "        \"content\": \"To find $3-a$, we will need to eliminate $b$ from the two equations given.\\n\\nFrom the first equation:\\n$3+a = 4-b$\\n\\nRearrange this to solve for $b$:\\n$b = 4-a$\\n\\nNow substitute this expression for $b$ in the second equation:\\n$4 + (4-a) = 7 + a$\\n\\nSimplify:\\n$3 = 3 + 2a$\\n$2a = 0$\\n$a = 0$\\n\\nNow we can find $b$:\\n$b = 4-0 = 4$\\n\\nFinally, we can find $3-a$:\\n$3-0 = 3$\\n\\n$\\\\boxed{3}$\",\n",
      "        \"role\": \"assistant\"\n",
      "      }\n",
      "    }\n",
      "  ],\n",
      "  \"created\": 1725338270,\n",
      "  \"model\": \"gpt-35-turbo\",\n",
      "  \"object\": \"chat.completion\",\n",
      "  \"prompt_filter_results\": [\n",
      "    {\n",
      "      \"prompt_index\": 0,\n",
      "      \"content_filter_results\": {\n",
      "        \"hate\": {\n",
      "          \"filtered\": false,\n",
      "          \"severity\": \"safe\"\n",
      "        },\n",
      "        \"self_harm\": {\n",
      "          \"filtered\": false,\n",
      "          \"severity\": \"safe\"\n",
      "        },\n",
      "        \"sexual\": {\n",
      "          \"filtered\": false,\n",
      "          \"severity\": \"safe\"\n",
      "        },\n",
      "        \"violence\": {\n",
      "          \"filtered\": false,\n",
      "          \"severity\": \"safe\"\n",
      "        }\n",
      "      }\n",
      "    }\n",
      "  ],\n",
      "  \"system_fingerprint\": \"fp_e49e4201a9\",\n",
      "  \"usage\": {\n",
      "    \"completion_tokens\": 7790,\n",
      "    \"prompt_tokens\": 52,\n",
      "    \"total_tokens\": 7842\n",
      "  },\n",
      "  \"cost\": 0.015684,\n",
      "  \"config_id\": 0,\n",
      "  \"pass_filter\": true\n",
      "}\n",
      "metric_results on the example data instance: {'expected_success': 0.9999999999999584, 'success': True, 'success_vote': 1.0, 'voted_answer': 'Given:\\n$3+a=4-b$ ...(1)\\n$4+b=7+a$ ...(2)\\n\\nCombining equations (1) and (2) to isolate $a$ and $b$:\\n\\n$3+a = 4-b \\\\implies a+b = 1$ ...(3)\\n$4+b = 7+a \\\\implies b-a = 3$ ...(4)\\n\\nAdding equations (3) and (4) gives:\\n$(a+b) + (b-a) = 1+3$\\n$2b = 4$\\n$b = 2$\\n\\nSubstitute $b=2$ into equation (3) gives:\\n$a+2 = 1 \\\\implies a = -1$\\n\\nNow that we have found the values of $a$ and $b$, we can find $3-a$:\\n\\n$3-a = 3 - (-1) = 3 + 1 = 4$\\n\\nTherefore, $\\\\boxed{4}$ is the value of $3-a$.', 'votes': 23}\n"
     ]
    }
   ],
   "source": [
    "response = autogen.ChatCompletion.create(context=tune_data[1], config_list=config_list, **config)\n",
    "metric_results = eval_math_responses(autogen.ChatCompletion.extract_text(response), **tune_data[1])\n",
    "print(\"response on an example data instance:\", response)\n",
    "print(\"metric_results on the example data instance:\", metric_results)"
   ]
  },
  {
   "cell_type": "markdown",
   "id": "28",
   "metadata": {},
   "source": [
    "### Evaluate the success rate on the test data\n",
    "\n",
    "You can use `autogen.ChatCompletion.test` to evaluate the performance of an entire dataset with the tuned config. The following code will take a while (~15 mins) to evaluate all the test data instances if uncommented and run. It will cost roughly $3. "
   ]
  },
  {
   "cell_type": "code",
   "execution_count": null,
   "id": "29",
   "metadata": {},
   "outputs": [
    {
     "data": {
      "application/vnd.livy.statement-meta+json": {
       "execution_finish_time": "2024-09-03T04:55:52.4359587Z",
       "execution_start_time": "2024-09-03T04:42:11.6230723Z",
       "livy_statement_state": "available",
       "normalized_state": "finished",
       "parent_msg_id": "0cbd0ca8-4365-4853-b0b9-55d16309b3d6",
       "queued_time": "2024-09-03T04:36:03.1992784Z",
       "session_id": "280727be-3509-4d73-817b-4c3fe9a4d244",
       "session_start_time": null,
       "spark_pool": null,
       "state": "finished",
       "statement_id": 73,
       "statement_ids": [
        73
       ]
      },
      "text/plain": [
       "StatementMeta(, 280727be-3509-4d73-817b-4c3fe9a4d244, 73, Finished, Available, Finished)"
      ]
     },
     "metadata": {},
     "output_type": "display_data"
    },
    {
     "name": "stdout",
     "output_type": "stream",
     "text": [
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      "evaluating data instance 200\n",
      "performance on test data with the tuned config: {'expected_success': 0.9988393536983416, 'success': 1.0, 'success_vote': 0.9303482587064676, 'votes': 38.24875621890547, 'cost': 3.1908739999999987, 'inference_cost': 0.015874995024875615}\n"
     ]
    }
   ],
   "source": [
    "result = autogen.ChatCompletion.test(test_data, logging_level=logging.INFO, config_list=config_list, **config)\n",
    "print(\"performance on test data with the tuned config:\", result)"
   ]
  },
  {
   "cell_type": "markdown",
   "id": "30",
   "metadata": {},
   "source": [
    "What about the default, untuned gpt-35-turbo-0125 config (with the same prompt as the tuned config)? We can evaluate it and compare:"
   ]
  },
  {
   "cell_type": "code",
   "execution_count": null,
   "id": "31",
   "metadata": {},
   "outputs": [
    {
     "data": {
      "application/vnd.livy.statement-meta+json": {
       "execution_finish_time": "2024-09-03T05:31:56.1089899Z",
       "execution_start_time": "2024-09-03T05:31:55.0161635Z",
       "livy_statement_state": "available",
       "normalized_state": "finished",
       "parent_msg_id": "d586b49e-3aa6-42c9-bfc8-3ca6d6761241",
       "queued_time": "2024-09-03T05:31:54.611734Z",
       "session_id": "280727be-3509-4d73-817b-4c3fe9a4d244",
       "session_start_time": null,
       "spark_pool": null,
       "state": "finished",
       "statement_id": 82,
       "statement_ids": [
        82
       ]
      },
      "text/plain": [
       "StatementMeta(, 280727be-3509-4d73-817b-4c3fe9a4d244, 82, Finished, Available, Finished)"
      ]
     },
     "metadata": {},
     "output_type": "display_data"
    },
    {
     "name": "stdout",
     "output_type": "stream",
     "text": [
      "performance on test data from gpt-35-turbo-0125 with a default config: {'expected_success': 0.7761194029850746, 'success': 0.7761194029850746, 'success_vote': 0.7761194029850746, 'votes': 1.0, 'cost': 0.09040799999999997, 'inference_cost': 0.0004497910447761193}\n"
     ]
    }
   ],
   "source": [
    "# the following code will cost roughly $0.1 if run.\n",
    "\n",
    "default_config = {\"model\": 'gpt-35-turbo-0125', \"prompt\": prompts[0], \"allow_format_str_template\": True}\n",
    "default_result = autogen.ChatCompletion.test(test_data, config_list=config_list, **default_config)\n",
    "print(\"performance on test data from gpt-35-turbo-0125 with a default config:\", default_result)"
   ]
  },
  {
   "cell_type": "code",
   "execution_count": null,
   "id": "32",
   "metadata": {},
   "outputs": [
    {
     "data": {
      "application/vnd.livy.statement-meta+json": {
       "execution_finish_time": "2024-09-03T04:59:59.3922097Z",
       "execution_start_time": "2024-09-03T04:59:59.0379376Z",
       "livy_statement_state": "available",
       "normalized_state": "finished",
       "parent_msg_id": "ae6bc657-6130-41f9-a016-22c1f578fc39",
       "queued_time": "2024-09-03T04:36:03.6578042Z",
       "session_id": "280727be-3509-4d73-817b-4c3fe9a4d244",
       "session_start_time": null,
       "spark_pool": null,
       "state": "finished",
       "statement_id": 75,
       "statement_ids": [
        75
       ]
      },
      "text/plain": [
       "StatementMeta(, 280727be-3509-4d73-817b-4c3fe9a4d244, 75, Finished, Available, Finished)"
      ]
     },
     "metadata": {},
     "output_type": "display_data"
    },
    {
     "name": "stdout",
     "output_type": "stream",
     "text": [
      "tuned config succeeds in 93.0% test cases\n",
      "untuned config succeeds in 77.6% test cases\n"
     ]
    }
   ],
   "source": [
    "print(\"tuned config succeeds in {:.1f}% test cases\".format(result[\"success_vote\"] * 100))\n",
    "print(\"untuned config succeeds in {:.1f}% test cases\".format(default_result[\"success_vote\"] * 100))"
   ]
  }
 ],
 "metadata": {
  "kernel_info": {
   "name": "synapse_pyspark"
  },
  "kernelspec": {
   "display_name": "Synapse PySpark",
   "language": "Python",
   "name": "synapse_pyspark"
  },
  "language_info": {
   "name": "python"
  },
  "nteract": {
   "version": "nteract-front-end@1.0.0"
  },
  "spark_compute": {
   "compute_id": "/trident/default"
  },
  "vscode": {
   "interpreter": {
    "hash": "949777d72b0d2535278d3dc13498b2535136f6dfe0678499012e853ee9abcab1"
   }
  }
 },
 "nbformat": 4,
 "nbformat_minor": 5
}
